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3 years ago

Please answer this correctly!

Mathematics

2 answers:

Kisachek [45]3 years ago

8 0

Answer:

1 1/4

2.2

The answers are in order as the questions.

ryzh [129]3 years ago

6 0

Answer:

1 1/4

Step-by-step explanation:

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Point Q'Q ′ Q, prime is the image of Q(0,6)Q(0,6)Q, left parenthesis, 0, comma, 6, right parenthesis under the translation (x,y)

Marina86 [1]

Q is located at (0,6)

The translation rule is $(x,y) \to (x+7,y-5)$ which says to add 7 to the x coordinate and subtract 5 from the y coordinate. Doing that to (0,6) moves it to (7,1) which is where point Q' is located.

In other words, if you shift point Q(0,6) seven units to the right and five units down, then it arrives at Q ' (7,1)

<h3>Answer: (7, 1)</h3>

8 0

3 years ago

Which transformations take f(x)=3x+1 to g(x)=−3x-5 ?

lbvjy [14]

<span>reflection over the x-axis and a translation 4 units down Refelcting f(x) over the x axis gives -f(x)=-3x-1 Subtracting a constant from -f(x) moves the graph of -f(x) that many units down. -f(x)-4=-3x-5=g(x) This shows that g(x) is obtained by reflecting f(x) over the x-axis and then translating 4 units down.</span>

8 0

3 years ago

Rewrite the function by completing the square<br><br> h(x)=4x^2+4x+1

lisov135 [29]

Answer:

$h(x) = 4(x+\frac{1}{2})^{2}$

Step-by-step explanation:

$h(x)=4x^2+4x+1\\h(x)=4(x^2+x+\frac{1}{4}) \\h(x)=4(x^2+x+\frac{1}{4})\\h(x) = 4(x+\frac{1}{2})^{2}$

8 0

2 years ago

Help me pleaseeeeeeee

puteri [66]

It would be the 30/3 one

7 0

3 years ago

Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist

Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

$\frac{70}{100}\times 60=42$

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

$\frac{75}{100}\times 42=31.5$

Number of students who need help in computer science and enrolled in his class after school hours

$\frac{30}{100}\times 60=18$

Therefore, there are $31.5+18=49.5$ students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

$\frac{49.5}{60}\times 100=82.5\%$

Hence, there are 82.5% after school students who are enrolled in his classes.

6 0

3 years ago