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3 years ago

Will give brainiest + 40 points Which graph represents the function p(x) = |x – 1|?

Mathematics

1 answer:

Vlad [161]3 years ago

6 0

Answer:

I think it's the second I e at the top

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1. Solve for y in the figure below.<br> X<br> 6<br> 8<br> 8

vichka [17]

there’s nothing there srry

4 0

3 years ago

NEED ASAP . Plz help

sladkih [1.3K]

It’s 4 and what they said

3 0

3 years ago

Plzzzzz help me on this and explain

Galina-37 [17]

The Answers are B and C
Its B because 12 is MORE than twice as much as M. Meaning 140 is larger than 2*m
Its C because again it is MORE than twice as much as M. Meaning that 140 is larger than 2m.

Answers;B,C
Hope this helped!

7 0

3 years ago

SOME ONE PLEASE HELP WITH THIS MATH QUIZ PLASE HONEST AWNSERS!!!

Liula [17]

Answer:

1. d 2. d 3. a

Step-by-step explanation:

1. factor

((w-4)(w-6))/((w-5)(w-6))+8/(w-5)

solve

(w-4)/(w-5)+8/(w-5)

(w+4)/(w-5), so d

2.factor

((b+2)(b-4))((b+2)(b-1))-6/(b-1)

solve

(b-4)/(b-1)-6(b-1)

(b-10)/(b-1), so d

3. (2/5t-3/3t)/(1/2t+1/2t)

(2/5t-1/t)/(2/2t)

(2/5t-1/t)/(1/t)

t(2/5t-1/t)

2/5-1=-3/5, so a

7 0

3 years ago

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

7 0

3 years ago