Answer:
the cost of running the boarding
house for 600 students is N61,000
Step-by-step explanation:
Let C represents cost
K1 represents first constant
K2 represents second constant
C= k1+k2n
3500 = k1 + 25 k2............. Eqn(1)
6000= k1 + 50 k2 .............. Eqn(2)
Subtract eqn(1) from eqn(2)
2500= 25k2
K2= 2500/25
K2= 100
To get k1 from eqn(1)
3500 = k1 + 25 k2
Substitute the value of k2
3500 = k1 + 25 (100)
3500= k1 +2500
K1= 3500- 2500
K1= 1000
The equation connecting them;
C= 1000+ 100n
The cost of running the boarding
house for 600 students is
n= 600
C= 1000+ 100(600)
C= 1000+60000
C= N 61,0000
C)-2/3is the answer because when your have 2/3+-2/3 will equal 0 in which justifies the additive inverse
Answer:
well i need a chart so when i see the chart i can help
Step-by-step explanation:
Answer:
A & C
Step-by-step explanation:
now, keeping in mind that a circular clock has 360° total, and there are 12 hours labeled on it evenly, so the angle between each hour label is 360 ÷ 12 = 30.
so, from 3pm to 5pm, it moved by 30° + 30° = 60°.
from 5pm to 5:30, that's only half an hour, so it moved half 30°, or 15°.
60° + 15° = 75°.
