Biological fitness, or Darwinian fitness, is an
organism's ability to survive to reproductive age and produce offspring.
The more offspring an organism produces, the greater its biological fitness
dr naJiiB ibraHim
Firstly, you should notice that for each 6moles of CO2 6moles of H2O is to be consumed in parallel for the reaction to occur. So it is 6:6 relation which means 1:1 relation. So whatever number of moles of CO2, the number of moles of H2O consumed should be exactly the same.
The equation to find the number of moles is:
#moles= mass used of the material/ molar mass of the material.
Now look closely, you only have both the used mass and the molar mass of CO2, and using the fact we mentioned before, so using the equation to find #moles of CO2 will give us a number that is exactly equal to the number of moles of H2O.
#moles of CO2= #moles of H2O= mass CO2/ molar mass CO2=

So #moles of H2O= 12mole.
Hope this helps.
Answer:
They would be the enzymes that assimilate the presence of Q to generate a metabolism that encourages growth.
And also those that are X-forming, which is what is always present in cells.
Explanation:
Therefore, all the enzymes that assimilate the amino acid Q continue to function.
In simple words, in this situation, amino acid Q went from being a non-essential amino acid (because it was manufactured in-house) to being an essential amino acid (which, if or if, must be administered by the medium due to lack of own production in order to generate growth) .
Answer:
For this reason, ammonia is considered basic because its nitrogen atom has an electron pair that readily accepts a proton
Explanation:
maybe you asked for _why are ammonia acid classified
if no I am sorry but your question seems a bit mistake
Answer:
This will happen in 39 years.
Explanation:
The population of the birds varies as A = A.e^kt
The population of birds fell from 1400 from 1000
Time it will take for the population to fall below 100 = x years.
when t = 0, population = 1400
t= 3; Population = 1000
Therefore:
1400 = 1000e^5k
e^5k= 1400/1000
k= (In 1.4)/5
we need to find x, such that
1400/1000= (e^xk)
14=(e^xk)
In(14) =kx
x= 5In(14)/In(1.4)
x= 39 years