Step 1. Factor out common terms in the first two terms, then in the last two terms.
2x^2(x - 5) -5(x - 5)
Step 2. Factor out the common term x - 5
(x - 5)(2x^2 - 5)
1.)
Old Number:35
New Number:45
Now, subract the new number(45) from the old number. (35)
45-35 is 10. Now divide the old number (35) by 10.
You'll get 3.5. 3.5%, increase is the answer for #1.
2.) Old: s (students)
New: 36,750
Do 100+5 (Addition because we do not know what the old number is.) 100+5 is 105. Move decimal over twice and you get 1.05. Multiply 36,750 by 1.05.
There were 38,587.5 kids last year.
3.)Since the discount is 15% off, do 100-15=85. Now, move the decimal over from the percent, and that makes that .85. Now multiply 50x.85. You get 42.5, or $42.50. Now the coupon is 10%, So subtract 100-10, giving you 90. Now move the decimal over. .90. Multiply 42.5 (or 42.50) by .90. You get 38.25. You do have enough money.
4.) Subtract 100-15, giving you 85. Move decimal over from percent. .85.
Now you would multiply .85 times k. B should be the answer.
-4x +12 -12 = -4 -12
-4x = -16
x = 4
Firstly, solve the effective annual interest (ieff) with the equation,
ieff = (1 + i/m)^m -1
where i is the interest rate and m is the number of times the interest is compounded in a year. In this problem, m is 12
Substituting the values,
ieff = (1 + 0.034/12)^12 - 1 =0.03453
To solve for the future (F) amount of the present investment (P),
F = P x (1 + ieff)^n
where n is number of years.
F = ($742) x (1 + 0.03453)^15
Thus, the answer is $1234.76.
