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Usimov [2.4K]
3 years ago
9

Pls help ill give brainliest to whoever answers

Mathematics
2 answers:
Eva8 [605]3 years ago
4 0

Answer: N snd B

Step-by-step explanation:

They have the same lines and they are the same shape.

mixas84 [53]3 years ago
4 0

Answer:

look up 1 on 3s

Step-by-step explanation: i did these test yesterday and the sit helped now plz give me brainlyest.

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can someone give me the answer please
Flauer [41]

Answer:

Point P.

Step-by-step explanation:

It is at the point -7 on x-axis and 4 on y-axis.

7 0
3 years ago
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26 × (-5 + 3)= step by step
lina2011 [118]

<em>Hello ~</em>

<em />

My name is lrxdscent, and I will be answering your question today! :D

Let's go by step-by-step ~

<h2>→ <u>Answer :-</u></h2>

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<u />\sf{= -52x}

<h2>→  <u>Explanation :-</u></h2>

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<u />\sf{26x \: (-5 \: + \: 3)

\sf{Add \: the \: numbers: \: -5 \: + \: 3 = -2}

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8 0
3 years ago
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Arnold's entire workout consisted of 10 minutes of warm up exercise, 25 minutes of lifting weights, and 15 minutes on the treadm
lord [1]

Add all the times together:

10 + 25 + 15 = 50 minutes total.

For the ratio divide the time for weights by total time:

25/50 which reduces to 1/2

The ratio is 1/2

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3 years ago
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HELPPP FIND THE AREA !!
Rashid [163]

Answer:

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Step-by-step explanation:

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3 years ago
Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

5 0
3 years ago
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