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balandron [24]
3 years ago
6

An Olympic sized swimming pool holds 6.6043×10^5 gallons of water. A standard garden hose can deliver 9 gallons of water per min

ute. If the garden hose was filling the pool 24 hours per day, how many days would it take to fill the olympic sized pool? Explain your reasoning
Mathematics
1 answer:
bixtya [17]3 years ago
5 0

6.6043×10^5 = 660,430 gallons.

660,430 / 9 = 73381.11... minutes.

73381.11... / 60 = 1223.01851852  hours.

1223.01851852 / 24 = 50.9591049383  days.

It would take about 51 days for the garden hose to fill the pool.

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A translation 2 units right and then a reflection over the x-axis

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A translation of ΔRST 2 units right gives;

(0 + 2, 0) = (2, 0), (-2 + 2, 3) = (0, 3), and (-3 + 2, 1) = (-1, 1), to give;

(2, 0), (0, 3), and (-1, 1)

A reflection of the point (x, y) across the x-axis gives (x, -y)

A reflection of the above points across the x-axis gives;

(2, 0) reflected about x-axis → (2, 0) reflected about x-axis → (0, -3), and (-1, 1)  reflected about x-axis → (-1, -1), which are the points of ΔR'S'T'

Therefore, the sequence of transformations that produces R'S'T' from RST are;

A translation 2 units right and then a reflection over the x-axis

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