36%=36/100=9/25
36% of 125=9/25*125=45 :)
V(t) = πr^2h
V'(t) = π(2rr'h + r^2h')
V'(t) = π(2(5)(-2)(7) + 5^2(8)
V'(t) = π(-140 + 200)
V'(t) = 60π in^3
Answer:
Step-by-step explanation:
The possible outcomes include 1, 2, 3, etc., up through 25. This in itself is insufficient to specify who will go first. There must be some further criteria.
Suppose each player chooses and announces a number from this set by writing it down on a scrap of paper which is placed face-down on the table. The person who chooses the smaller number goes first. Or, the person who chooses the larger number goes first.
2x + y = 3
3x - y = 12
Add both equations
5x = 15, x = 3
2(3) + y = 3
6 + y = 3, y = -3
Solution: x = 3, y = -3... or (3,-3)
Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=initial term, d=common difference, n=term number
In this case a=5, and d=-2 so
a(n)=5-2(n-1) which can be simplified...
a(n)=5-2n+2
a(n)=7-2n
The domain is restricted to integers from 1 to +oo.
