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Darina [25.2K]
3 years ago
10

Graph compound inequality on number line x <1 and x<3

Mathematics
2 answers:
Sliva [168]3 years ago
4 0

Answer:

j

Step-by-step explanation:

andre [41]3 years ago
3 0

See attachment for answer.

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(Pts: 1) Please help me! Question is in attachment!
Sloan [31]
- - Solve:

To find the volume of a sphere:
 \frac{4}{3} *3.14*R^3

3.14≈π

Now since its telling us to use π, then we do our formula by multiplying by π.

π=3.14 (Approximate amount)

So:

4/3*3.14*9^3=3052.08

So you are correct.

When Radius=9, you plug in for R. :)

8 0
3 years ago
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If (x + k) is a factor of f(x), which of the following must be true?
KIM [24]

Answer:

<h3>f(-k)=0</h3>

Step-by-step explanation:

(x + k) is a factor of f(x)

x+k=0 => <u>x= -k;</u>    <em>-k is a root of f(x)</em>

=> f(-k)=0

6 0
3 years ago
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Fill in the blank: A piecewise function uses different rules for different intervals of the _________.
Bogdan [553]
<span>A piecewise function uses different rules for different intervals of the DOMAIN</span>
5 0
3 years ago
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You want to study how the number of popped kernels in a microwave popcorn bag is affected by brand, microwave power, and time in
Afina-wow [57]

Answer:

Number of unique treatment combinations  = 8

Step-by-step explanation:

Given:

Number of brands = 3

Number of power settings = 2

Number of microwave times = 3

Find:

Number of unique treatment combinations.

Computation:

Number of unique treatment combinations = Number of brands + Number of power settings + Number of microwave times

Number of unique treatment combinations = 3 + 2 + 3

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8 0
3 years ago
Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2
valentina_108 [34]

Answer:

Solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

Step-by-step explanation:

We need to solve the equation x^2+6x-8=0 by completing the square method.

For completing the square method: we need to follow: a^2+2ab+b^2=(a+b)^2

We are given:

x^2+6x-8=0

Solving by completing the square

x^2+2(x)(?)+(?)^2-8=0

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17

So, solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

7 0
3 years ago
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