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3 years ago

Which of the following statements about an ellipse is NOT true?

Mathematics

1 answer:

jeyben [28]3 years ago

7 0

Answer: (b) The focus of an ellipse is always located precisely at the center of the ellipse.

Step-by-step explanation:

An ellipse is defined as <em>"a closed curve with two axes of symmetry (major axis and minor axis) that results in cutting the surface of a cone by an oblique plane to the axis of symmetry with an angle greater than that of the generatrix with respect to the axis of revolution"</em>. That is why the ellipse is considered a conic figure.

To understand it better: an ellipse has two points on its major axis that are equidistant from the center , which are called foci, being this distance constant. In addition, the eccentricity allows to know how far the foci are from the center of the ellipse.

Therefore, the statement that indicates an ellipse has only one focus located precisely at the center is incorrect.

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The width of a human hair is 2 x 10-5 meters. The width of a piece of sand is 1.5 x 10¹ meters.

Elena L [17]

The difference in the widths, in meters, of the human hair and the piece of sand is $1.4998*10^{-1}$ m.

It is given in the question that:-

Width of a human hair = $2*10^{-5}$ m

Width of a piece of sand = $1.5*10^{-1}$ m

We have to find the difference in the widths, in meters, of the human hair and the piece of sand.

We know that,

Difference between the widths = Width of a piece of sand - Width of a human hair

Hence, we can write,

Difference between the widths = $2*10^{-5}$ m - $1.5*10^{-1}$ m

We can write,

$1.5*10^{-1}=15000*10^{-5}$

Hence,

Difference between the widths =

$15000*10^{-5} - 2*10^{-5}= 14998*10^{-5} = 1.4998*10^{-1}$ m

To learn more about Width, here:-

brainly.com/question/17156323

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8 0

2 years ago

If a geometric sequence has a2 = 495 and a6 = 311, approximate the value of the common ratio ???? to four decimal

shtirl [24]

Answer:

$r = 0.8903$

Step-by-step explanation:

given,

a₂ = 495

a₆ = 311

geometric sequence formula

$a_n = ar^{n-1}$

$a_2 = ar^{2-1}$

$a_2 = ar$ ...................(1)

$a_6 = ar^{6-1}$

$a_6 = ar^5$ ................(2)

dividing equation (2) by (1)

$\dfrac{a_6}{a_2} = \dfrac{ar^5}{ar}$

$\dfrac{311}{495} = r^4$

$r^4 = 0.628$

$r = 0.8903$

hence, the common ratio of the geometric sequence is $r = 0.8903$

7 0

3 years ago

The figure below shows the quotient of fraction 1 over 2 divided by fraction 1 over 6.

bekas [8.4K]

1
-----
2 1 (6)
-------- = ---------- = 3 (answer) 1/6 divides into 1/2 3 times.
1 2 (1)
----
6

3 0

3 years ago

wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0

Andreyy89

Answer:

$E_n=34,467,075.42\ N/C$

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

$\displaystyle E=K\cdot \frac{Q}{d^2}$

Where

$K = 9\cdot 10^9\ Nw.m^2/c^2$

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge $q_1=+6.24\mu C=6.24\cdot 10^{-6}C$ is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

$\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}$

$E_1=37,888,345.42\ N/C$

Similarly, for $q_2=-9.55\mu C=-9.55\cdot 10^{-6}C$ , the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right: