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postnew [5]
3 years ago
6

Which of the following statements about an ellipse is NOT true?

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer: (b) The focus of an ellipse is always located precisely at the center of the ellipse.

Step-by-step explanation:

An ellipse is defined as <em>"a closed curve with two axes of symmetry (major axis and minor axis) that results in cutting the surface of a cone by an oblique plane to the axis of symmetry with an angle greater than that of the generatrix with respect to the axis of revolution"</em>. That is why the ellipse is considered a conic figure.

To understand it better: an ellipse has two points on its major axis that are equidistant from the center , which are called foci,  being this distance constant. In addition, the eccentricity allows to know how far the foci are from the center of the ellipse.

Therefore, the statement that indicates an ellipse has only one focus located  precisely at the center is incorrect.

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FIND THE SUM AND THE DIFFERENCE FOR EACH PAIR OF POLYNOMIALS please show work
Pepsi [2]

Answer:

12a. Addition = 7y⁵ + 7y³ – 6y – 5

12b. Subtraction = – y⁵ – 3y³ + 8y + 11

13a. Addition = 5x⁴ + x³ – 6x² + 8x + 17

13b. Subtraction = – x⁴ – 9x³ –6x² + 8x + 3

14a. Addition = – 2b⁴ + b³ – 11b² – 1

14b. Subtraction = 4b⁴ + 7b³ – b² + 8b – 1

15a. Addition = m⁵ + m⁴ + m³ + m²

15b. Subtraction = m⁵ – m⁴ – m³ – m² – 10

16a. Addition = 4x⁴ + 12x³ + 18x² + 16x + 4

16b. Subtraction = 4x⁴ – 4x³ + 14x² – 16x + 4

Step-by-step explanation:

12a. Addition

.. 3y⁵ + 2y³ + y + 3

+ (4y⁵ + 5y³– 7y – 8)

————————————

= 7y⁵ + 7y³ – 6y – 5

12b. Subtraction

.. 3y⁵ + 2y³ + y + 3

– (4y⁵ + 5y³– 7y – 8)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= – y⁵ – 3y³ + 8y + 11

13a. Addition

.. 2x⁴ – 4x³ – 6x² + 8x + 10

+ (3x⁴ + 5x³ +...................+ 7)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 5x⁴ + x³ – 6x² + 8x + 17

13b. Subtraction

.. 2x⁴ – 4x³ – 6x² + 8x + 10

– (3x⁴ + 5x³ +...................+ 7)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= – x⁴ – 9x³ – 6x² + 8x + 3

14a. Addition

...... b⁴ + 4b³ – 6b² + 4b – 1

+ (– 3b⁴ – 3b³ – 5b² – 4b)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= – 2b⁴ + b³ – 11b² – 1

14b. Subtraction

...... b⁴ + 4b³ – 6b² + 4b – 1

– (– 3b⁴ – 3b³ – 5b² – 4b)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 4b⁴ + 7b³ – b² + 8b – 1

15a. Addition

... m⁵ + m³ – 5

+ (m⁴ + m² + 5)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= m⁵ + m⁴ + m³ + m²

15b. Subtraction

... m⁵ + m³ – 5

– (m⁴ + m² + 5)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= m⁵ – m⁴ – m³ – m² – 10

16a. Addition

.... 4x⁴ + 8x³ + 16x² + 4

+ (4x³ + 2x² + 16x)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 4x⁴ + 12x³ + 18x² + 16x + 4

16b. Subtraction

.... 4x⁴ + 8x³ + 16x² + 4

– (4x³ + 2x² + 16x)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 4x⁴ – 4x³ + 14x² – 16x + 4

3 0
2 years ago
Please help ASAP it’s due in 4 minutes
maxonik [38]

Answer:

a) well we know the hypotenuse and we know that all sides are 90 degrees, and that its an even square, so if we split it into a triangle , we know that the other 2 angles are 45 degrees total, with this we can calculate  the other 2 sides, which round to 10 inches.

b) if we know the sides of the first side, knowing the fact that its a square we know that all sides are even, therefore, all sides are 10 inches, the formula the finding the perimeter is basic:

P=L(2) + W(2)

L being length, W being width and P being perimeter

so we add up all 4 sides, here is the equation:

10 + 10 + 10 + 10 = 10 x 4 = 40

With this, we know that the perimeter is 40 inches total

c) knowing how long the sides are, we can figure out the area through another basic formula:

A=L X W

With A meaning Area

since its a square, we know all the sides are even, so the width and length are both 10...

10 X 10 = 100

Step-by-step explanation:

I Hope I Helped!

3 0
3 years ago
The perimeter of this isosceles triangle is 22 cm. If one side is 6 cm, what are the possible lengths of the other two sides? Pa
3241004551 [841]
We know that

<span>the isosceles triangle has two equal sides
</span>
<span>let's analyze two cases
</span>
first case
perimeter=22 cm
<span>let's suppose that the known side of 6 cm is one of the two equal sides
</span>perimeter=6+6+x
22=6+6+x-----> x=22-12----> x=10 cm

answer first case
<span>the possible lengths of the other two sides are
</span>6 cm 
10 cm

second case
let's suppose that the known side of 6 cm is the side that is not equal
perimeter=22 cm
perimeter=6+x+x
22=6+x+x----> 2x=22-6----> 2x=16-----> x=8 cm


answer second case
the possible lengths of the other two sides are
8 cm 
8 cm

4 0
3 years ago
PLZ HELP QUICK WILL MARK BRAINLIEST
slega [8]
For the Fist One it’s Pentagonal Pyramid
5 0
3 years ago
Draw a rectangle with an area of 42 square units
Butoxors [25]
We know, Area = Length * Width

So, with area 42, dimensions could be: 1 * 42
2 * 21
3 * 14
6 * 7

Just draw the lines with that measures, two pair of two equal opposite lines.

Hope this helps!

6 0
3 years ago
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