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3 years ago

Find the accumulated value of $ 740 at the end of 7 years using a nominal annual rate of interest of 6 % compounded quarterly.

Business

1 answer:

GaryK [48]3 years ago

5 0

Answer:

$1122.74

Explanation:

We are to find the future value of $740

The formula for calculating future value:

FV = P (1 + r/m)^nm

FV = Future value

P = Present value

R = interest rate = 6

N = number of years = 7

m = number of compounding = 4

$740 x (1 + 0.06/4)^7x4 = $1122.74

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If the Fed sells $2 million of bonds to the First National Bank, what happens to reserves and the monetary base?

Sindrei [870]

Answer:

Reserves fall by $2 million, and the monetary base falls by $2 million.

Explanation:

In the books of First National Bank, the purchase of $2 million of bonds by First National Bank, from the Federal Reserve means there is a reserve with the Federal Reserve represented by security which stands as asset.

In the books of the Federal Reserve, The sales of bonds to First National Bank will create a liability from the reserve assets.

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3 years ago

A manager who makes a situation more efficient could be described as a(an) leader formulator strategist implementer

Nataliya [291]

The answer is an implementer. A manger who is an implementer not only makes situations more efficient for his workers but also more reliable. A formulator on the other hand is some who innovates. A formulator thinks outside of the box and would often want dramatic results.

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3 years ago

How have airplanes changed the way the world does business? choose four answers

Rama09 [41]

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2 years ago

Madison Foods Corp. is frustrated in its efforts to sell products in Europe because several countries are demanding that the com

mixer [17]

Answer: Trade obstacle

Explanation:

From the information given, we can infer that the demands are examples of trade obstacle.

Trade obstacles refers to the barriers which hinder a trade or the restrictions on an international trade. Trade obstacles can be tariffs or other non-tariff methods. Trade obstacles lead to difficulties in the sale of a product to other countries.

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3 years ago

Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital

shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= $\frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}$

= $\frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}$

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

$\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}$

using K/N = k

$\frac{s}{\delta +n-s}.\frac{n}{kt}$

plugging the value of kt*

$\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}$

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) = n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0

3 years ago