All categories

3 years ago

Please help!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

4 0

Answer:

145 lb

Step-by-step explanation:

416 x 5(oz) = 2080

(Now to convert oz to lb)

2080 ÷ 16 = 130

The apples are 130 pounds, now to add the barrel's weight

130 + 15 = 145

You might be interested in

8. A rain barrel collected 75 gallons of water. Water leaked

Mnenie [13.5K]

Answer:

30 days (do correct me if I'm wrong haha)

Step-by-step explanation:

5 gallons = 2 days

75 gallons = 30 days

75÷5=15 15×2=30

7 0

3 years ago

PLEASE ANSWER ASAP!!!!

Arlecino [84]

We'll use the notation $\textrm{Arcsin } x$ for the principal value and $\arcsin x$ for all the values:

$\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k$

Part I

$\sin(\theta/2) = \frac 1 2$

$\theta/2 = \arcsin \frac 1 2$

Part II. In our range we can write

$\sin(\theta/2) = \sin(\frac \pi 6)$

$\theta/2 = \frac \pi 6 \textrm{ or } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}$

Part III.

$\theta = \frac \pi 3 \textrm{ or } \theta = \frac{5\pi}{3}$

Part IV.

$\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k$

$\theta = \frac \pi 3 + 4 \pi k \textrm{ or } \theta = \frac{5 \pi}{3} + 4\pi k \quad \textrm{integer } k$

5 0

3 years ago

Write the equation of circle b with center B(-2,3) that passes through (1,2)

professor190 [17]

Answer:

$(x+2)^2 + (y-3)^2 = 10$

Step-by-step explanation:

The standard equation for circle is

$(x-a)^2 + (y-b)^2 = r^2$

where point (a,b) is coordinate of center of circle and r is the radius.

______________________________________________________

Given

center of circle =((-2,3)

let r be the radius of circle

Plugging in this value of center in standard equation for circle given above we have

$(x-a)^2 + (y-b)^2 = r^2 \ substitute (a,b) \ with (-2,3) \\=>(x-(-2))^2 + (y-3)^2 = r^2 \\=>(x+2)^2 + (y-3)^2 = r^2 (1)$

Given that point (1,2 ) passes through circle. Hence this point will satisfy the above equation of circle.

Plugging in the point (1,2 ) in equation 1 we have

$\\=>(x+2)^2 + (y-3)^2 = r^2 \\=> (1+2)^2 + (2-3)^2 = r^2\\=> 3^2 + (-1)^2 = r^2\\=> 9 + 1 = r^2\\=> 10 = r^2\\=> r^2 = 10\\$

now we have value of r^2 = 10, substituting this in equation 1 we have

Thus complete equation of circle is $=>(x+2)^2 + (y-3)^2 = r^2\\=>(x+2)^2 + (y-3)^2 = 10$

7 0

3 years ago

What is the volume of the right prism with height h=14 cm, if the base of the prism is a triangle ∆ABC with side AB = 9 cm and a

LenaWriter [7]

Answer:

378

Step-by-step explanation:

9*6=54 then 54/2=27. fnally 27*14=378

6 0

3 years ago

Read 2 more answers

Give the values of a, b, and c needed to write the equation's general form.. (5 + x)(5 - x) = 7. A = 1; B = 0; C = -18. A = 25;

Licemer1 [7]

The general form of an equation is $A x^{2} +Bx+C=0$ . Solving for (5+X)(5-X)=7 by multiplying the factors and subtratcting 7 on both sides gives the equation $x^{2} -18=0$ , so
A = 1
B = 0
C = -18

6 0

3 years ago