Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
Answer:
Step-by-step explanation:
Answer:
y<2/3x-1
Step-by-step explanation:
plotted point is on -1
slope of the line is rise 2, run 3
so its the last option
Answer:
a) 0.1535
b) 0.4866
c) 0.8111
Step-by-step explanation:
The probability that the next call come within the next t minutes is:
According to this model,
a) the probability that a call in comes within 1/2 minutes is 
=0.1535
b) the probability that a call in comes within 2 minutes is 
=0.4866
c) the probability that a call in comes within 5 minutes is 
=0.8111
