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2 years ago

6

A plot of grass behind a building is shown.

2 answers:

KATRIN_1 [288]2 years ago

3 0

Answer:

62m

Step-by-step explanation:

16+16+8+12+10

=62m

Juliette [100K]2 years ago

3 0

62m———- no explanation

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Share 56 sweets in the ratio 2 : 5.

kherson [118]

Answer is 16:40

Add up the parts of the sweets so 2+5=7.
Then with the total amount (56)/7=8.
8x2= 16
8x5=40

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

2 years ago

14x=x^2-15<br><br> find the value of x

hram777 [196]

Answer: $x=-1, 15$

Step-by-step explanation:

$x^2 -14x-15=0\\\\(x-15)(x+1)=0\\\\x=-1, 15$

5 0

1 year ago

The sum of two numbers is 53 . The larger number is 9 more than the smaller number. What are the numbers?

Illusion [34]

x + y = 53

x -y = 9 Adding both equations

2x = 62

x = 31 y = 22

6 0

2 years ago

Write an appropriate direct variation equation if y = 27 when x = 9

Yuri [45]

Y = kx where k is a constant

27 = k*9
k = 27/9 = 3

required variation is y = 3x

4 0

3 years ago

Read 2 more answers