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3 years ago

Koby can work about 22 math problems in 30 minutes. At this rate how many math problems can Koby work in 3 hours

Mathematics

2 answers:

Veronika [31]3 years ago

7 0

The answer is 132 problems, I hope this helps

Murrr4er [49]3 years ago

4 0

132 problems because...

there are six 30 minutes in 3 hours so you would multiply 22 with 6 to get 132
(22*6=132)

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Stuart's bank account had a balance of - $54.19 last month. This month he won a cash prize of $70.82 for winning a competition.

Alenkinab [10]

If Stuart starts with -$54.19 then gains $70.82, you have to add the gained amount to the origin amount. Since the origin amount is negative, you can also subtract the origin amount from the gained amount to find the amount left at the end of the month.

Add 70.82 to -54.19

-54.19 + 70.82 = 16.63

<u>Alternative method:</u>

First, subtract 54.19 from 70.82.

70.82 - 54.19 = 16.63

Add 54.19 to -54.19, bringing you to 0.

-54.19 + 54.19 = 0

Now add the remaining 16.63.

0 + 16.63 = 16.63

<h2>Answer:</h2>

<u>Stuart will have </u><u>$16.63</u><u> at the end of this month.</u>

7 0

3 years ago

Help plz i don't know if it is add subtract or division or timesing

Mashutka [201]

You would add the fabric price, the craft glue and paper price. then you subtract your total from the $16.95.

6 0

3 years ago

Read 2 more answers

The lines of symmetry in a regular polygon are equal to the number of sides minus 2. True or False

galina1969 [7]

Answer:

False

Step-by-step explanation:

A regular polygon may be defined as the polygon that have sides of equal length known as equilateral and angles made up of equal angles, known as equiangular.

The $\text{number of lines}$ of symmetry in a regular polygon is always equal to the number of sides of the polygon. For example, a regular pentagon have 5 sides, so the lines of symmetry of the regular pentagon is also 5, a square having 4 sides also has 4 lines of symmetry.

6 0

3 years ago

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym Tw

mr_godi [17]

Answer: (15th street, 14th Avenue)

Step-by-step explanation:

Given the following :

Ping's residence = (3rd street, 6th Avenue)

Ari's residence = (21st street, 18th Avenue)

Gym location = 2/3 the distance of Ping's residence to Ari's residence

So, distance between Ping's home to Ari's home

Distance = (21st street, 18th Avenue) - (3rd street, 6th Avenue)

Distance = (21 - 3) street, (18 - 6) avenue

Distance between ping and Ari = (18th , 12th )

Gym distance = 2/3 of distance between ping and Ari

Gym distance = 2/3 × (18), 2/3 ×(12)

Gym distance = (12, 8)

Gym location = Ping's location + gym distance

Gym location = (3rd street, 6th Avenue) + (12th street, 8th Avenue)

Gym location = (15th street, 14th Avenue)

3 0

3 years ago

Use Lagrange multipliers to solve the following exercise. A home improvement contractor is painting the walls and ceiling of a r

mash [69]

Answer:

Let the width of the garden =x meter

Then length=(x+4) meter

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74⇒4x=64⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

5 0

3 years ago