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Stella [2.4K]
3 years ago
12

Convert: 16 c =________gal

Mathematics
1 answer:
tester [92]3 years ago
5 0

Answer:

16 cups is 1 gallon

Step-by-step explanation:

because there are 16 cups in a gallon

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Wally had two more marbled than ashan and together they have 88 marbles how many marbles does ashan have
labwork [276]
Represent as
w=wally
a=ashan
so wally has 2 more marbles than ashan
w=2+a

together they have 88
w+a=88

since w=2+a, subsitute (2+a) for w in the w+a=88 equation
2+a+a=88
add like terms
2+2a=88
subtract 2 from both sides
2a=86
divide by 2
a=43

ashan has 43 marbles
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What does the some of triangles always equal?
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Answer:

the angles always equal 180

Step-by-step explanation:

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The lines graphed below are parallel. The slope of the red line is -4/3. What is the slope of the green line?
miss Akunina [59]
I believe the correct answer from the choices listed above is option C. The slope of the green line would be -4/3. Parallel lines <span> are </span>lines<span> in a plane which do not meet; that is, two </span>lines<span> in a plane that do not intersect or touch each other at any point. These lines should have equal slopes. Hope this answers the question.</span>
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Find the p and q that produce the Pythagorean triple (3, 4, and 5). Please help me, please and thank you! =)
IgorC [24]

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Step-by-step explanation:

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What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x
konstantin123 [22]

Answer:

f(x)=x^{3}-3x^{2} +4x-2

Step-by-step explanation:

we know that

The <u><em>conjugate root theorem</em></u> states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial

In this problem we have that

The polynomial has roots 1 and (1+i)

so

by the conjugate root theorem

(1-i) is also a root of the polynomial

therefore

The lowest degree of the polynomial is 3

so

f(x)=a(x-1)(x-(1+i))(x-(1-i))

Remember that

The leading coefficient is 1

so

a=1

f(x)=(x-1)(x-(1+i))(x-(1-i))\\\\f(x)=(x-1)[x^{2} -(1-i)x-(1+i)x+(1-i^2)]\\\\f(x)=(x-1)[x^{2} -x+xi-x-xi+2]\\\\f(x)=(x-1)[x^{2} -2x+2]\\\\f(x)=x^{3}-2x^{2} +2x-x^{2} +2x-2\\\\f(x)=x^{3}-3x^{2} +4x-2

5 0
4 years ago
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