Answer:
we will have to multiply the second equation by 3 to eliminate the y variable by adding.
Step-by-step explanation:
Given the equations
4x – 3y = 6 → (1)
6x + 2y = 10 → (2)
As the first equation is multiplied by 2,
2(4x – 3y) = (2)6
8x - 6y = 12 → (3)
As we have to eliminate y,
so multiply the second equation by 3,
6x + 2y = 10
3(6x + 2y) = 3(10)
18x + 6y = 30 → (4)
So now adding the new equations (3) and (4) will eliminate the y variable by adding
8x - 6y = 12
18x + 6y = 30
--------------------
26x + 0y = 42
26x = 42
x = 42/26
x = 21/13
Therefore, we will have to multiply the second equation by 3 to eliminate the y variable by adding.
Answer:
(Hope this helps can I pls have brainlist (crown) and 5 star rating? ☺️)
Step-by-step explanation:
Simplifying
2e + 10 = 16
Reorder the terms:
10 + 2e = 16
Solving
10 + 2e = 16
Solving for variable 'e'.
Move all terms containing e to the left, all other terms to the right.
Add '-10' to each side of the equation.
10 + -10 + 2e = 16 + -10
Combine like terms: 10 + -10 = 0
0 + 2e = 16 + -10
2e = 16 + -10
Combine like terms: 16 + -10 = 6
2e = 6
Divide each side by '2'.
e = 3
Simplifying
e = 3
adius is 30.1 astronomical units (AU). assuming neptunes orbit is circular, ... The distance it travels in a single orbit around the sun is ... Its orbital radius is 30.130.130, point, 1 astronomical units (\text{AU})(AU)left parenthesis, start text, A, U, end text, right parenthesis.
Answer:
the answer is fairly simple just look at the table and analyze the data.
Step-by-step explanation:
question 1 asks for the "reference point", id say the reference point is at 3 seconds when the dog begins moving.
question 2 is asking if the dog was in motion for the first 3 seconds, the answer is "no" because if you take a look at the table the distance is the same for the first 3 seconds.
question 3 is asking when the dog was in motion the correct answer is at 4 seconds when the dog moves from 10 meters to 20 meters, and that'll be your evidence. hope this helps!!