<h2>
Answer with explanation:</h2>
Formula to find the confidence interval for population proportion (p) is given by :-
, where z* = Critical value.
= Sample proportion.
SE= Standard error.
Let p be the true population proportionof U.S. adults who live with one or more chronic conditions.
As per given , we have
SE=0.012
By z-table , the critical value for 95% confidence interval : z* = 1.96
Now , a 95% confidence interval for the proportion of U.S. adults who live with one or more chronic conditions.:
Hence, a 95% confidence interval for the proportion of U.S. adults who live with one or more chronic conditions.
Interpretation : Pew Research Foundation can be 95% confident that the true population proportion (p) of U.S. adults who live with one or more chronic conditions lies between 0.42648 and 0.47352 .
An equation is formed of two equal expressions. The correct option is C.
<h3>What is an equation?</h3>
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
The image of the two functions is given below. Since the solution of the two systems of equations is (-3,-4). Therefore, we can write f(–3) = g(–3).
Hence, the correct option is C.
Learn more about Equation:
brainly.com/question/2263981
#SPJ1
Total marbles = 2 + 7 = 9
P(Purple, then white) = (7/9)(2/8) = 7/36
Answer: 7/36
Answer:
56.42 minutes
Step-by-step explanation:
The initial sample= y0 = 800
After 13 minutes , amount = 320
Y= y0e-kt
320 = 800e-k(13)
320/800 = e-k13
0.4 = e-k13
In0.4 = -k13
-0.91629= -k13
0.07048= k
Y = 800e-0.07048t
Minutes when the bacterial present will be 15
15 = 800e-0.07048t
15/800= e-0.07048t
0.01875 = e-0.07048t
In 0.01875 = -0.07048t
-3.97656 = -0.07048t
-3.97656/-0.07048= t
56.42 = t
56.42 minutes
