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adelina 88 [10]
3 years ago
13

Let the vector \mathbf{v}v have an initial point at (-5, -5)(−5,−5) and a terminal point at (-3, 1)(−3,1). Determine the compone

nts of vector \mathbf{v}.V.
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

Answer:

The components of the vector are x = 2 and y = 6, respectively.

Step-by-step explanation:

The components of the vector is equal to the vector position of the terminal point relative to the initial point (\vec v), that is:

\vec v = B(x,y) - A(x,y) (1)

Where:

A(x,y) - Initial point.

B(x,y) - Terminal point.

If we know that A(x,y) = (-5,-5) and B(x,y) = (-3,1), then the vector is:

\vec v = (-3,1) -(-5-5)

\vec v = (2, 6)

The components of the vector are x = 2 and y = 6, respectively.

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Emily estimated it would take her 40 minutes to run 3 miles. It actually took her 30 minutes. What was Emily's percent of error
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Answer:

C. 33.3%

Step-by-step explanation:

Estimated time = 40 minutes

Actual time = 30 minutes

Percent of error = (estimated time - actual time) / actual time × 100

= (40 minutes - 30 minutes) / 30 minutes × 100

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6 0
3 years ago
Hi! Please help!!
STatiana [176]

9514 1404 393

Answer:

  (c)  9, 24, 26

Step-by-step explanation:

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The "form factor" of f = a^2 +b^2 -c^2, where c is the longest side length, can signal the kind of triangle it is. f=0 indicates a right triangle (values satisfy the Pythagorean theorem). When there are a lot of numbers to try, I like to let a calculator or spreadsheet do the math. (See attached).

As indicated above, the 9-24-26 triple cannot be a right triangle. For f < 0, it will be an obtuse triangle.

4 0
3 years ago
1. Find the lengths of the diagonals of rectangle QRST , Given that QS = 6X+3 and RT = 8X-1
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Answer:

1. QS and RT= 15

2. Im not positive but I think it's TQ=18

Step-by-step explanation:

For question 1, you would do 6x+3=8x-1 and solve to get the result of x=2

Then you'd plug in 6 and get QS and RT=15

For the second one I am unsure because I wasn't positive how to solve but it seems like the side RQ might be 1/2 of TQ. Sorry if thats wrong I can try and help more if you need

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