Permutation helps us to know the number of ways an object can be arranged in a particular manner. The correct option is D.
<h3>What are Permutation and Combination?</h3>
Permutation helps us to know the number of ways an object can be arranged in a particular manner. A permutation is denoted by 'P'.
The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.
The example which is an example of permutation is Selecting a first-, second-, and third-place winner at baking.
Hence, the correct option is D.
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9514 1404 393
Answer:
a) 600
b) see below
c) 1.26 hours
Step-by-step explanation:
a) The value of y when x=0 is the coefficient of the exponential term:
y = 600·3^(-0) = 600·1 = 600
There were 600 atoms to start.
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b) see attached for a graph
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c) The graph shows 150 atoms at t = 1.26, about 1.26 hours after the start of time counting.
If you want to find that value algebraically, substitute for y and solve for x. Logarithms are involved.
150 = 600·3^(-x)
150/600 = 3^(-x)
log(1/4) = -x·log(3)
x = -log(1/4)/log(3) = log(4)/log(3) ≈ 1.2618595
After about 1.26 hours, there were 150 atoms.
Answer:
5 months
Step-by-step explanation:
Given


Required [Missing from the question]
At what month will the cost be equal
To do this, we equate both expressions

This gives:

Collect like terms


Solve for m


Answer:
Required difference = 270/19 km
Step-by-step explanation:
If we consider the AP of distances to be
a, a + r, a + 2r, ..., a + 19r,
where a is the distance of the nearest location from the port and r is the difference between any two successive location.
Given that,
a + 19r = 300 .....(1)
a = 30 ..... (2)
Using (2), from (1), we get
30 + 19r = 300
or, 19r = 300 - 30
or, 19r = 270
or, r = 270/19
Therefore the distance between any two successive location is 270/19 km.
Answer:
7 feet
Step-by-step explanation:
Pythagorean theorem
sqrt(4.5^2 + 5.3^2) = hypotenuse
sqrt(48.34) = hypotenuse
6.95269732 = hypotenuse
round to nearest tenth
7 feet = the length of the hypotenuse