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Lisa [10]
3 years ago
9

Shannon is selling boxes cookies and candy for a fundraiser. She's sold each box of cookies for $5.25. She also sold one one box

of candies for $8.75.
Shannon set a goal to sell at least $200 of cookies and candies for her fundraiser.

What was the minimum boxes of cookies Shannon needed to sell to reach her goal?

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

The minimum boxes of cookies is 39

Step-by-step explanation:

Let

x ----> the number of boxes of cookies sold

y ----> the number of boxes of candies sold

we know that

The word "at least" means "greater than or equal to"

so

The inequality that represent this problem is

5.25x+8.75y\geq 200

The solution is the shaded area above the solid line   5.25x+8.75y=200

using a graphing tool

The solution is the shaded area -----> see the attached figure

Find out the minimum boxes of cookies needed to sell to reach the goal

assuming only cookies are sold

For y=0

5.25x+8.75(0)\geq 200

5.25x\geq 200

solve for x

x\geq 38.1

Round up

therefore

The minimum boxes of cookies is 39

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Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.

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Hence, the underground height of the dog after t seconds is given by:

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Answer:

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