Shannon is selling boxes cookies and candy for a fundraiser. She's sold each box of cookies for $5.25. She also sold one one box
of candies for $8.75.
Shannon set a goal to sell at least $200 of cookies and candies for her fundraiser.
What was the minimum boxes of cookies Shannon needed to sell to reach her goal?
Shannon set a goal to sell at least $200 of cookies and candies for her fundraiser.
What was the minimum boxes of cookies Shannon needed to sell to reach her goal?
1 answer:
Answer:
The minimum boxes of cookies is 39
Step-by-step explanation:
Let
x ----> the number of boxes of cookies sold
y ----> the number of boxes of candies sold
we know that
The word "at least" means "greater than or equal to"
so
The inequality that represent this problem is
The solution is the shaded area above the solid line
using a graphing tool
The solution is the shaded area -----> see the attached figure
Find out the minimum boxes of cookies needed to sell to reach the goal
assuming only cookies are sold
For y=0
solve for x
Round up
therefore
The minimum boxes of cookies is 39
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Answer:
see below
Step-by-step explanation:
If we let X represent the number of bagels produced, and Y the number of croissants, then we want ...
(a) Max Profit = 20X +30Y
(b) Subject to ...
6X +3Y ≤ 6600 . . . . . . available flour
X + Y ≤ 1400 . . . . . . . . available yeast
2X +4Y ≤ 4800 . . . . . . available sugar
_____
Production of 400 bagels and 1000 croissants will produce a maximum profit of $380.
__
In the attached graph, we have shaded the areas that are NOT part of the solution set. (X and Y less than 0 are also not part of the solution set, but are left unshaded.) This approach can sometimes make the solution space easier to understand, since it is white.
The vertex of the solution space that moves the profit function farthest from the origin is the one we are seeking. The point that does that is (X, Y) = (400, 1000).
