(1)Identify the surface whose equation is r = 2cosθ by converting first to rectangular coordinates...(2)Identify the surface whose equation is r = 3sinθ by converting first to rectangular coordinates...(3)Find an equation of the plane that passes through the point (6, 0, −2) and contains the line x−4/−2 = y−3/5 = z−7/4...(4)Find an equation of the plane that passes through the point (−1,2,3) and contains the line x+1/2 = y+2/3 = z-3/-1...(5)Find a) the scalar projection of a onto b b) the vector projection of a onto b given = 〈2, −1,3〉 and = 〈1,2,2〉...(6)Find a) the scalar projection of a onto b b) the vector projection of a onto b given = 〈2,1,4〉 and = 〈3,0,1〉...(7)Find symmetric equations for the line of intersection of the planes x + 2 y + 3z = 1 and x − y + z = 1...(8)Find symmetric equations for the line of intersection of the planes x + y + z = 1 and x + 2y + 2z = 1...(9)Write inequalities to describe the region consisting of all points between, but not on, the spheres of radius 3 and 5 centered at the origin....(10)Write inequalities to describe the solid upper hemisphere of the sphere of radius 2 centered at the origin....(11)Find the distance between the point (4,1, −2) and the line x = 1 +t , y = 3 2−t , z = 4 3−t...(12)Find the distance between the point (0,1,3) and the line x = 2t , y = 6 2−t , z = 3 + t...(13)Find a vector equation for the line through the point (0,14, −10) and parallel to the line x=−1+2t, y=6-3t, z=3+9t<span>...</span>
20/100 in simplest form is 1/5
Answer:
y = (-14/15) x + (11/15)
Explanation:
The slope-intercept form has the following formula:
y = mx + c
where:
m is the slope
c is the y-intercept
The given is:
14x + 15y = 11
To put this in slope-intercept form, we will need to isolate the y as follows:
14x + 15y = 11
15y = -14x + 11
y = (-14/15) x + (11/15)
were:
m is the slope = -14/15
c is the y-intercept = 11/15
Hope this helps :)
For this case we have to, by defining properties of powers and roots the following is fulfilled:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
We must rewrite the following expression:
![\sqrt [3] {8 ^ {\frac {1} {4} x}}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B8%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B4%7D%20x%7D%7D)
Applying the property listed we have:
![\sqrt [3] {8 ^ {\frac {1} {4} x}} = 8 ^ {\frac{\frac {1} {4} x} {3} }= 8 ^ {\frac {1} {4 * 3} x} = 8 ^ {\frac {1} {12} x}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B8%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B4%7D%20x%7D%7D%20%3D%208%20%5E%20%7B%5Cfrac%7B%5Cfrac%20%7B1%7D%20%7B4%7D%20x%7D%20%7B3%7D%20%7D%3D%208%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B4%20%2A%203%7D%20x%7D%20%3D%208%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B12%7D%20x%7D)
Using the property again we have to:
![8 ^ {\frac {1} {12} x} = \sqrt [12] {8 ^ x}](https://tex.z-dn.net/?f=8%20%5E%20%7B%5Cfrac%20%7B1%7D%20%7B12%7D%20x%7D%20%3D%20%5Csqrt%20%5B12%5D%20%7B8%20%5E%20x%7D)
Thus, the correct option is option C
Answer:
Option C