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Lisa [10]
2 years ago
9

Shannon is selling boxes cookies and candy for a fundraiser. She's sold each box of cookies for $5.25. She also sold one one box

of candies for $8.75.
Shannon set a goal to sell at least $200 of cookies and candies for her fundraiser.

What was the minimum boxes of cookies Shannon needed to sell to reach her goal?

Mathematics
1 answer:
defon2 years ago
5 0

Answer:

The minimum boxes of cookies is 39

Step-by-step explanation:

Let

x ----> the number of boxes of cookies sold

y ----> the number of boxes of candies sold

we know that

The word "at least" means "greater than or equal to"

so

The inequality that represent this problem is

5.25x+8.75y\geq 200

The solution is the shaded area above the solid line   5.25x+8.75y=200

using a graphing tool

The solution is the shaded area -----> see the attached figure

Find out the minimum boxes of cookies needed to sell to reach the goal

assuming only cookies are sold

For y=0

5.25x+8.75(0)\geq 200

5.25x\geq 200

solve for x

x\geq 38.1

Round up

therefore

The minimum boxes of cookies is 39

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3x+y=115x-y=21 Directions: Solve each system of equations by elimination. Clearly identify your solution.
olchik [2.2K]

To solve, we will follow the steps below:

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1 year ago
the probability that Jenya receives spam email is 4%.if she receives 520 email in a week about how much will be spam
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3 years ago
Please this is your answer.​
Effectus [21]

Answer:

10. it is correct it is 24

11. 21

Step-by-step explanation:

I could not see the answer but it should look like this:

11.6-3(3-[2-3]-10)-3

6-3(3-[-1]-10)-3

6-3(3-(-1)-10)-3

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4 0
2 years ago
Read 2 more answers
How do u do this because I forgot
neonofarm [45]

I don't know which one you want but here

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OR

Decimal form

x=0.9

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2 years ago
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