Hmm, one way we can do this is by assigning numbers to each
A=4 and B=3
A>B because 4>3
so
A. 2(A+B)=2(4+3)=2(7)=14
B. A+B^2=4+3^2=4+9=13
C. A^2+B^2=4^2+3^2=16+9=25
D. A^2-B^2=4^2-3^2=16-9=7
the largest is 25 so C
Answer:
25% most likely
Step-by-step explanation:
If you divide the numbers by 100 then you get ez answer XD
Answer:
$49.60
Step-by-step explanation:
The equation setup I used for this was as follows: $16 x (112/36)
Using PEMDAS, you'd start with the division part, 112/36. Although, I did this a bit differently, and being a bit further in school, I don't know if you go through this where you're at.
Start by factoring 112 into 4(28). This leaves you with 4(28)/36.
Next, cancel 4 out of 36. Since 4 is the common factor in 28 and 36, you cancel the four out of the equation, leaving you with 28/9. Convert this to its decimal form, 3.1.
Finally, take the 3.1 and multiply that by $16, which comes out to $49.60.
Answer:
unlock code is 11
A= 27
B=16
C=1
(11)^1 = 11
Step-by-step explanation:
