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3 years ago

Which is an example of using the distributive property to multiply?

Mathematics

1 answer:

FrozenT [24]3 years ago

6 0

Answer:

option-B

Step-by-step explanation:

we are given

$-5x^3(3x^2+3x-1)$

we can use distributive property

Distributive property:

$a(x+y+z)=a\cdot x+a\cdot y+a\cdot z$

now, we can apply this formula

and we get

$-5x^3(3x^2+3x-1)=-5x^3\cdot 3x^2-5x^3\cdot 3x-5x^3\cdot -1$

we can see that there are two negative signs in last term

so, we can write as

$-5x^3(3x^2+3x-1)=-5x^3\cdot 3x^2-5x^3\cdot 3x+5x^3\cdot 1$

so,

option-B

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A square patio has an area of 150 square feet. how long is each side of the patio to the nearest tenth?

Solnce55 [7]

length of each side of the patio to the nearest tenth is 12.247 ft.

<h3>How to find the length of each side of the patio to the nearest tenth?</h3>

given that A square patio has an area of 150 square feet.

we know that area of square is

${a}^{2} = 150 \\ a = \sqrt{150} \\ a = 12.247 \: ft$

therefore, length of each side of the patio to the nearest tenth is 12.247 ft.

Learn more about area of square, refer:

brainly.com/question/25092270

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2 years ago

Figure ABCDE was reflected across the line y=x to create figure A’B’C’D’E’.What are the coordinates of the pre-image of E’?

Minchanka [31]

Answer:

the answer is -2,6

Step-by-step explanation:

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3 years ago

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Please I need help with differential equation. Thank you

Inga [223]

1. I suppose the ODE is supposed to be

$\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)$

Solving for $\dfrac{\mathrm dy}{\mathrm dt}$ gives

$\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}$

which is undefined when $t=\pm1$ . The interval of validity depends on what your initial value is. In this case, it's $t=-\dfrac12$ , so the largest interval on which a solution can exist is $-1\le t\le1$ .

2. Separating the variables gives

$\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}$

Integrate both sides. On the left, we have

$\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}$

where we substituted $z=y^{1/2}$ - or $z^2=y$ - and $2z\,\mathrm dz=\mathrm dy$ - or $\mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}$ .

$\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)$

On the right, we have

$\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)$

$\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C$

$2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C$

$\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C$

$y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}$

$y^{1/2}=C(1-t^2)^{1/4}-1$

I'll leave the solution in this form for now to make solving for $C$ easier. Given that $y\left(-\dfrac12\right)=1$ , we get

$1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1$

$2=C\left(\dfrac54\right)^{1/4}$

$C=2\left(\dfrac45\right)^{1/4}$

and so our solution is

$\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}$

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3 years ago

Which of the following statements is true about systematic random sampling?

frutty [35]

C is the right answer answer but I gotta is a great time to go home to the right one or the other one is the right one and you have to answer me by the heart and

I hope this helps you!

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2 years ago

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nevsk [136]

Answer:

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its 2 o clock rn here

Step-by-step explanation:

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3 years ago

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