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Mademuasel [1]
3 years ago
8

Write the quadratic equation in general quadratic form below 3x^2 + 6x = 12

Mathematics
2 answers:
scZoUnD [109]3 years ago
5 0

Answer: 3x^{2}+6x-12=0

Step-by-step explanation:

By definition a quadratic equation in general quadratic form is:

ax^{2}+bx+c=0

Therefore, to write the equation given in the problem above in in general quadratic form, you only need to subtract 12 from both sides of the equation.

Keeping this on mind, you obtain:

3x^{2}+6x-12=12-12\\3x^{2}+6x-12=0

Ilya [14]3 years ago
5 0

Answer:

3x²+6x-12 = 0

Step-by-step explanation:

We have given a quadratic equation.

3x²+ 6x = 12

We have to rewrite above equation in general quadratic equation.

The general form of quadratic equation is:

ax²+bx+c = 0 where a,b and c are constant.

Adding -12 to both sides of given equation, we have

3x²+6x+(-12) = 12+(-12)

3x²+6x-12 = 12-12

3x²+6x-12 = 0 is general form of quadratic equation where a = 3,b = 6 and c = -12.

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1) 13 + 3W - 9 + 16w
nevsk [136]

Answer:

4+19W

Step-by-step explanation:

You would just simplify the terms, 13-9=4 and 3W+16W=19W

5 0
3 years ago
Read 2 more answers
10 points
dsp73

Answer:

A

Step-by-step explanation:

I hope this helps and sorry if I'm wrong!

4 0
2 years ago
Solving quadratic formulas<br> 8y²-30y+27=2
Bess [88]
Y=5/2, 5/4 your welcome
6 0
2 years ago
List all the perfect cubes up to 1000 and their cube roots.
DiKsa [7]

Hello from MrBillDoesMath!

Answer:

1^3    =     1

2^3   =     8

3^3   =     27

4^3   =     64

5^3   =    125

6^3   =    216

7^3   =    343

8^3  =     512

9^3   =    729

10^3   =    1000

Thank you,

MrB


4 0
3 years ago
State how many imaginary and real zeros the function has.
myrzilka [38]
Hello,
Degre 5==> even number of imaginary roots and odd number of reals.

Real roots must be a divisor of 7.
Using Excel, we find


<span> <span><span> x  P(x) 
 </span><span>-7 0 </span>
<span> -6 1369
</span> <span> -5 1352
</span> <span> -4 867
</span> <span> -3 400
</span> <span> -2 125
</span> <span> -1 24
 </span><span>0 7
 </span><span>1 32
 </span><span>2 225
 </span><span>3 1000
 </span><span>4 3179
 </span><span>5 8112
 </span><span>6 17797
 </span><span>7 35000

So: one real root: 7 and 4 imaginary roots.

Answer B
 </span></span></span>
7 0
3 years ago
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