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3 years ago

How much will each person get if 4 people share 1/2 pound of grapes equally

2 answers:

7 0

Hey there!

To solve this, divide the numbers 1/2 and 4 . . .

1/2 = 1/2

4 = 4/1

1 x 1 = 1

2 x 4 = 8

The fraction 1/8 is already in it's simplest form, so it does not need to be simplified.

1/8 pounds of grapes can be shared equally among the 4 friends.

Hope this helps you.
Have a great day!

dsp733 years ago

3 0

Divide amount of grapes by number of people.

= 1/2 lb ÷ 4 people

to divide a fraction, multiply by the reciprocal (inverse)

= 1/2 * 1/4
= (1*1)/(2*4)
= 1/8 pound

ANSWER: Each of the 4 people will get 1/8 pound of grapes.

Hope this helps! :)

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Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that $A \cap B$ = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

$A + (A \cap B) = 0.40$

$A + 0.17 = 0.40$

$A = 0.23$

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

$B + (A \cap B) = 0.35$

$B + 0.17 = 0.35$

$B = 0.18$

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

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3 years ago

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Here we have x = 59,969 and n= 461,299

P = x/n = 59969/461299

P = 0.13

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