Six. 2 1/3=7/3-> to get to have a denominator of 6 multiply by 2 to get 14/6
Then 1/2=3/6
14/6 + 3/6 = 17/6
17/6= 2 5/6
Percent = 75%
base = unknown ...the base is the number that follows " of "
amount = 30
Answer:
About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Standard deviation = 17.
About what percentage of births would be expected to occur within 51 days of the mean pregnancy length?
51/17 = 3.
So, within 3 standard deviations of the mean.
About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length
Steps:
Shape: Sphere
Solved for volume
Radius: 3
Formula: V=4
/3πr3
1: know the height. We don't have to round to the nearest tenth. The correct answer for this question is 113.0.
Answer: 113.0
<em><u>Please mark brainliest</u></em>
<em><u>Hope this helps.</u></em>
Answer:
The least number of hours that she would have to work is 11.
Step-by-step explanation:
First, make the equation be "12.75x +100=235". Then, subtract 10 from both sides of the equation. You would get
"12.75x= 135". Then, divide both sides of the equation by 12. 75x, and the equation turns out to say, "x=10.59".
