How do I find volume of a sphere with 10 as the diameter?

Mathematics

1 answer:

allsm [11]3 years ago

8 0

Answer:

166.67 pi

Step-by-step explanation:

V = 4/3 * pi * r^3

= 4/3 * pi * 5^3

= 166.67 pi

You might be interested in

Frozen motts sticks cost $.022 each. If there are 6 sticks in on order, what is the portion cost for an order of motts sticks?

solong [7]

Answer:

$ 1.32

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

Cost of each Mott's Stick = $0.22 .

Now there are 6 sticks in an order . So the cost of six sticks will be ,

→ Cost = $ 0.22 × 6

→ Cost = $ 1.32

<h3>Hence the cost of an order of sticks is $ 1.32 </h3>

8 0

3 years ago

Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.

SSSSS [86.1K]

Answer:

$\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}$

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

$-x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}$

6 0

3 years ago

The nature of a graph, which has an even degree and a positive leading coefficient will be

zaharov [31]

The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position

<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>

The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.

Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.