(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
Answer:
6750J
Step-by-step explanation:
30^2=900 900x15=13500 13500/2=6750
domain of the problem is -5 and the range is 4
If A=750+135N; and B=485N, then A+B=
750+135N+485N=750+620N
T=620N+750
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