Option C:
x = 6 units
Solution:
QR = 7 units, RS = 5 units, UT = 4 units and ST = x
<em>If two secants intersect outside a circle, the product of the secant segment and its external segment s equal to the product of the other secant segment and its external segment.</em>
⇒ SR × SQ = ST × SU
⇒ 5 × (5 + 7) = x × (x + 4)
⇒ 5 × 12 = x² + 4x
⇒ 60 = x² + 4x
Subtract 60 from both sides.
⇒ 0 = x² + 4x - 60
Switch the sides.
⇒ x² + 4x - 60 = 0
Factor this expression, we get
(x - 6)(x + 10) = 0
x - 6 = 0, x + 10 = 0
x = 6, x = -10
Length cannot be in negative measures.
x = 6 units
Option C is the correct answer.
You have to multiply how many pounds Jake can carry and how many pounds Jake's dad can carry.
2-(-4)
--------= 6
-1-7 ---= 3/4
8
y=3/4x
-4=3/4 (7)+b
-4=21/4+b
-4-21/4= -37/4
21/4-21/4=0
y=3/4x-37/4
Y-4=3(x-(-2))
Simplifying you get
y-4=3(x+2)
How many boxes are there in total?
