The equation for this parabola satisfies
(in other words, plug in each given point's coordinates into the equation )
Now,
and
So the equation of the parabola is
Calculate them all.
a)16x+5(2x+8)-14=16x+10x+40-14=26+26x
b)26-2(3x)=26-6x
c)6x-28+10(x+4)-14=6x-28+10x+40-14=16x-2
d)26-6x
There are two equivalent ones, which give no real majority...
D. NI = AC is the needed information to prove ΔINF = ΔCAT by the ASA Postulate.
For the triangles to be congruent by ASA, the measurements of two angles and one side must be proven congruent. Since two sets of congruent angles are already given, one side must also be congruent.
When proving congruency using ASA, the congruent parts of the triangles must be in this order: Angle, Side, Angle. So, you have to the side that is between the two sets of congruent angles.
Answer: 5/6
WORKINGS
The denominator of 3/4 is 4
The fraction we are to write has a denominator of 6
Lowest common multiple of 4 and 6 is 12
Therefore, we have to re-write 3/4 with 12 as the denominator
Multiply both numerator and denominator of 3/4 by 33/4 = 9/12
Since 1 = 12/12
The fractions are less than 1, but greater than 3/4 are therefore, 10/12 and
11/12
Reduce both numbers to their lowest factor
10/12 = 5/6
11/12 cannot be further reduced
Therefore, the fraction less than 1 with denominator of 6 that is greater than 3/4 is 5/6
Answer:
157???
Step-by-step explanation:
I don't really know how to do this