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Alik [6]
3 years ago
9

In a high-school, 135 freshmen were interviewed.

Mathematics
1 answer:
charle [14.2K]3 years ago
6 0

Answer:

\dfrac{118}{135}

Step-by-step explanation:

Total Number of Students =135

Number who took all three subjects=5

Number who took PE and BIO=10

Number who took PE and ENG=15

Number who took BIO and ENG=7

Therefore:

  • Number who took PE and BIO only=10-5=5
  • Number who took PE and ENG only=15-5=10
  • Number who took BIO and ENG only =7 -5=2

Total Number of students who took exactly two subjects=5+10+2=17

Therefore:

Number of students who did not take exactly two subjects=135-17=118

The probability that a randomly-chosen student from this group did not take exactly two subjects

=\dfrac{\text{Number of students who did not take exactly two subjects}}{\text{Total Number of students }} \\=\dfrac{118}{135}

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-4(2x-3)>-28 please i need this result
Len [333]

-4 (2x - 3) > -28

Divide by -4 on both sides. Since we're dividing by a negative, we need to switch the sign.

2x - 3 < 7

Add 3 to both sides

2x < 10

Divide by 2 on both sides

x < 5

3 0
3 years ago
Jim Tree sells trees. The mean length of the trees purchased was 68 inches with a standard deviation of 10 inches. Jim wants to
Zepler [3.9K]

Step-by-step explanation:

We know that,

Z=\dfrac{X-\mu}{\sigma}

Where,

X = raw score = 84

μ = mean = 68

σ = standard deviation = 10

Putting the values,

Z=\dfrac{84-68}{10}=1.6

The percent of his sales that were less than or equal to 84 inches, is

P(Z\leq 1.6)=0.9452=94.52\%\approx 94.5\%

Therefore, the remaining 100-94.5=5.5% were more than 84 inches.

4 0
3 years ago
How much interest is earned on $2,700 in one year if it is invested at 3%?
Natalka [10]
$81 is earned by investing $2700 in one year at 3%.
3 0
4 years ago
Please help I’m really confused and need to learn this
egoroff_w [7]

Answer:

2.

Step-by-step explanation:

For #2, another way to word this question is: For which of the following trig functions is π/2 a solution? Well, go through them one by one. If you plug π/2 into sinθ, you get 1. This means that when x is π/2, y is 1. Try and visualize that. When y is 1, that means you moved off the x-axis; so y = sinθ is NOT one of those functions that cross the x-axis at θ = π/2. Go through the rest of them. For y = cos(π/2), you get 0. At θ = π/2, this function crosses the x-axis. For y = tanθ, your result is undefined, so that doesn't work. Keep going through them. You should see that y = secθ is undefined, y = cscθ returns 1, and y = cotθ returns 0. If you have a calculator that can handle trig functions, just plug π/2 into every one of them and check off the ones that give you zero. Graphically, if the y-value is 0, the function is touching/crossing the x-axis.

Think about what y = secθ really means. It's actually y = 1/(cosθ), right? So what makes a fraction undefined? A fraction is undefined when the denominator is 0 because in mathematics, you can't divide by zero. Calculators give you an error. So the real question here is, when is cosθ = 0? Again, you can use a calculator here, but a unit circle would be more helpful. cosθ = π/2, like we just saw in the previous problem, and it's zero again 180 degrees later at 3π/2. Now read the answer choices.

All multiples of pi? Well, our answer looked like π/2, so you can skip the first two choices and move to the last two. All multiples of π/2? Imagine there's a constant next to π, say Cπ/2 where C is any number. If we put an even number there, 2 will cut that number in half. Imagine C = 4. Then Cπ/2 = 2π. Our two answers were π/2 and 3π/2, so an even multiple won't work for us; we need the odd multiples only. In our answers, π/2 and 3π/2, C = 1 and C = 3. Those are both odd numbers, and that's how you know you only need the "odd multiples of π/2" for question 3.

6 0
3 years ago
Yo can yall help me need help to pass
kari74 [83]

Answer:

(3, 5)

Step-by-step explanation:

Point (3, -5) is 5 units below the x-axis.

After it is reflected, it will be 5 units above the x-axis.

Answer: (3, 5)

3 0
3 years ago
Read 2 more answers
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