x=31,y=−61
Put the equations in standard form and then use matrices to solve the system of equations.
5x+4y=1,3x−6y=2
Write the equations in matrix form.
(534−6)(xy)=(12)
Left multiply the equation by the inverse matrix of (534−6).
inverse((534−6))(534−6)(xy)=inverse((534−6))(12)
The product of a matrix and its inverse is the identity matrix.
(1001)(xy)=inverse((534−6))(12)
Multiply the matrices on the left hand side of the equal sign.
(xy)=inverse((534−6))(12)
For the 2×2 matrix (acbd), the inverse matrix is (ad−bcdad−bc−cad−bc−bad−bca), so the matrix equation can be rewritten as a matrix multiplication problem.
(xy)=(5(−6)−4×3−6−5(−6)−4×33−5(−6)−4×345(−6)−4×35)(12)
Do the arithmetic.
(xy)=(71141212−425)(12)
Multiply the matrices.
(xy)=(71+212×2141−425×2)
Do the arithmetic.
(xy)=(31−61)
Extract the matrix elements x and y.
x=31,y=−61
It’s 3! 3x4 is 12 and 5 isn’t a factor of 12
C
Angle 1 and 2 make up a straight angles and straight angles always equal 180.
Subtract 35 from 180 to find Angle 2s measure which is 145
The answer is 36. If this is wrong I am truly sorry v.v
Answer:
M(t) = 4/3 * pi * (4t + 3)^3
Step-by-step explanation:
W(t) = radius after t seconds,
Substitute W(t) for r in V(r)
Since W(t) = 4t +3:
M(t) = 4/3 * pi * (4t+3)^3
