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3 years ago

I need help fast the answers fro each question are in the drop down menu

Mathematics

2 answers:

kiruha [24]3 years ago

8 0

Alternate exterior angles

MrRissso [65]3 years ago

6 0

Alternate exterior angles

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Solve for x. -3.5x = -35

r-ruslan [8.4K]

Answer:

$- 3.5x = - 35 \\ x = \frac{ - 35}{ - 3.5}( - \div - = + ) = \frac{35}{35 \times .1} \\ = \frac{1}{.1} = 10 \\ x = 10 \\ thank \: you$

7 0

3 years ago

Read 2 more answers

The last line of a proof represents

ki77a [65]

Answer:

It represents the given information

Step-by-step explanation:

7 0

3 years ago

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

4 years ago

What is the surface area of this triangular pyramid?<br> ___square inches

IrinaVladis [17]

Answer:

Surface area = 10.7 in.²

Step-by-step explanation:

Surface Area of triangular pyramid = BA + P*L

Base Area (BA) = ½*nh

b = 2 in.

h = 1.7 in.

BA = ½*2*1.7 = 1.7 in.²

Perimeter (P) = 2 + 2 + 2 = 6 in.

Slant height (L) = 3 in.

Plug in the values

Surface Area = 1.7 + ½*6*3

Surface area = 10.7 in.²

5 0

3 years ago

1. Li needs to buy 2 kilograms of apples. If she buys 9 apples that each weigh approximately 150 grams, will she have enough? Ex

Lelechka [254]

1. Li will not have enough apples. This is because 9 apples that each weigh approximately 150 grams would weigh a total of 1.35kg.

2. The caterpillar weighs 65.2 grams.

Hope this helps!

4 0

3 years ago