Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Diagonals that bisect each other are perpendicular and form a right angle.
AEB is a right triangle.
We can apply the Pythagorean theorem:
c^2 = a^2+b^2
Where c is the hypotenuse (longest side) and a and b the other 2 legs.
Replacing:
AB^2 = AE^2+BE^2
AB^2 = 5^2+12^2
AB^2 = 25+144
AB^2 = 169
AB=√169 = 13
Lenght of AB= 13
Something along the lines of this...
-28x-11
Step-by-step explanation:
10x-38x=-28x
+36-47=-11
so the answer is -28x-11
Answer:
Measure of angle A = 55°.
Step-by-step explanation:
From the picture attached,
2 = 2
Corresponding sides of the given triangles ΔACB and ΔNLM are proportional.
Therefore, ΔACB ~ ΔNLM.
m∠A = 180° - (90° + 35°) [By triangle sum theorem]
= 180° - 125°
= 55°
Measure of angle A is 55°.
