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Naya [18.7K]
3 years ago
7

ANSWER QUICKLY!!!

Mathematics
2 answers:
NikAS [45]3 years ago
8 0

Answer:Reflection about the y-axis followed by a translation to the left by 2 units

Step-by-step explanation:I took the test

Ganezh [65]3 years ago
6 0

It was reflected. this is bc it is the same shape, just flipped.

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The following information was obtained from independent random samples taken of two populations. Assume normally distributed pop
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Answer:

1. The 95% confidence interval for the difference between means is (-5.34, 11.34).

2. The standard error of (x-bar1)-(x-bar2) is 4.

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=10 has a mean of 45 and a standard deviation of √85=9.2195.

The sample 2, of size n2=12 has a mean of 42 and a standard deviation of √90=9.4868.

The difference between sample means is Md=3.

M_d=M_1-M_2=45-42=3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4

The critical t-value for a 95% confidence interval is t=2.086.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=2.086 \cdot 4=8.34

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 3-8.34=-5.34\\\\UL=M_d+t \cdot s_{M_d} = 3+8.34=11.34

The 95% confidence interval for the difference between means is (-5.34, 11.34).

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