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3 years ago

ANSWER QUICKLY!!!

Mathematics

2 answers:

NikAS [45]3 years ago

8 0

Answer:Reflection about the y-axis followed by a translation to the left by 2 units

Step-by-step explanation:I took the test

Ganezh [65]3 years ago

6 0

It was reflected. this is bc it is the same shape, just flipped.

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First twelve numbers<br> Add 15, subtract 10 (first term: 4)

astra-53 [7]

Answer:

1st- 4, 2nd- 9, 3rd- 14, 4th- 19, 5th- 24, 6th- 29, 7th- 34, 8th- 39, 9th- 44, 10th- 49, 11th- 54, 12th-59

Step-by-step explanation:

1st- 4

2nd- 4+15-10= 9

3rd- 9+15-10=14

4th- 14+15-10=19

5th- 19+15-10=24

6th- 24+15-10=29

7th- 29+15-10=34

8th- 34+15-10=39

9th- 39+15-10=44

10th- 44+15-10=49

11th- 49+15-10=54

12th-54+15-10=59

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3 years ago

PLSSSS HELP ME ALOT OF CREDITS AND BRAINLIST IF YOU HELP ME!!!!!

Pachacha [2.7K]

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By probability in the chart, it goes from most to least that is grapes, apples, bananas and oranges

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3 years ago

Help plz:))) I’ll mark u brainliest <br> ASAP!!!

alekssr [168]

Answer:

x = 13

Step-by-step explanation:

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3 years ago

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Use the zero product property to find the solutions to the equation 6x2 – 5x = 56.

Reika [66]

Answer:

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Step-by-step explanation:

5 0

3 years ago

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A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

3 0

3 years ago