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densk [106]
3 years ago
13

We have 500 mice and want to determine how effective a given cure for a virus. 10 mice are taken from the group and injected wit

h our cure. 7 mice were cured. According to this experiment, how many mice should be cured?
Mathematics
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

350

Step-by-step explanation:

if you take 500-10 that gives you 490 left to cure if 7 of those 10 are cured the 350 out of the total mice would be cured.   if it is not the correct answer i am sorry that is just how I was taught to do it.

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hammer [34]
394 is the answer using addition
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3 years ago
Evaluate the expression when m=4.<br> m^2 + 6m + 8
Vikki [24]

Answer:

According to me,

<h2>48 is the answers</h2>
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3 years ago
Below is a proof showing that the sum of a rational number and an irrational number is an irrational number.
ankoles [38]

Answer:

Step-by-step explanation:

To prove: The sum of a rational number and an irrational number is an irrational number.

Proof: Assume that a + b = x and that x is rational.

Then b = x – a = x + (–a).

Now, x + (–a) is rational because addition of  two rational numbers is rational (Additivity property).

However, it was stated that b is an irrational number. This is a contradiction.

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4 0
3 years ago
Read 2 more answers
What is 39+21g when g = -4
timurjin [86]

Answer:

-45

Step-by-step explanation:

When the -4 is plugged in, it needs to be multiplied and then added to 39. That equals -45.

8 0
3 years ago
Read 2 more answers
Partial fraction decomposition<br> 20x+9/25x^2+20x+4
ozzi

Step-by-step explanation:

We have

\frac{20x + 9}{25 {x}^{2} + 20x + 4 }

Let's factor the denomiator first,

the denomaitor is a perfect square so we get

\frac{20x + 9}{(5x + 2) {}^{2} }

Now, we must think of two fractions that

\frac{a}{(5x + 2) {}^{2} }  +  \frac{b}{5x + 2}

We use a perfect square term for one fraction, then a linear one for the next, because if we set both of the denomiator to the same factor, we would get a inconsistent system.

So right now, we have

\frac{a}{(5x + 2) { }^{2} }  +  \frac{b}{5x + 2}  =  \frac{20x +9 }{25 {x}^{2} + 20x + 4 }

a + (5x  + 2)b = 20x + 9

5b (x)= 20

a + 2b = 9

b = 4

so that means that a is

a + (2)(4) = 9

a + 8 = 9

a = 1

So our equation is

\frac{1}{(5x + 2) {}^{2} }  +  \frac{4}{5x + 2}

6 0
3 years ago
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