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1 year ago

If x is 1 what is the value of y?9x - 5y = 29

Mathematics

1 answer:

mylen [45]1 year ago

4 0

Given

The equation,

9x - 5y = 29.

To find the value of y when x is 1.

Explanation:

It is given that,

$9x-5y=29$

That implies,

When x=1,

$\begin{gathered} 9(1)-5y=29 \\ 9-5y=29 \\ -5y=29-9 \\ -5y=20 \\ y=\frac{20}{-5} \\ y=-4 \end{gathered}$

Hence, the value of y is -4.

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2 years ago

A is the point with coordinates (3,8) b is the point with coordinates (x,13) the gradient of an is 2.5 .work out the value of x

Solnce55 [7]

Answer:

x = 5

Step-by-step explanation:

The formula for the gradient is given by:

m = (y2 - y1)/(x2 - x1), where two points (x1, y1) and (x2, y2) are given.

Thus if we have a gradient of 2.5 and two points (3, 8) and (x, 13), we can substitute this into the above formula for the gradient to get:

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3 years ago

What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?

miv72 [106K]

A geometry app shows lengths that add up to 27.4 units.

The Pythagorean theorem can be used to find the lengths of the segments. Each length is the square root of the sum of squares of the difference in x-coordinates and the difference in y-coordinates.

segment AB: length = √(3²+8²) = √73 ≈ 8.544

segment BC: length = √(7²+4²) = √65 ≈ 8.062

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2 years ago

Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th

butalik [34]

Answer:

a). The mean = 1000

The variance = 999,000

The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

= 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean = $\mu = \frac{1}{p}$

= $\mu = \frac{1}{0.001}$

= 1000

Variance = $\sigma ^2=\frac{1-p}{p^2}$

= $\sigma ^2=\frac{1-0.001}{0.001^2}$

= 999,000

The standard deviation is determined by the root of the variance.

$\sigma = \sqrt{\sigma^2}$

= $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000 times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

= $ 0.50

Since the answer is negative, we are expected to make a loss.

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2 years ago