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2 years ago

Anyone know this answer 15e^3/3e simplify

Mathematics

1 answer:

SSSSS [86.1K]2 years ago

4 0

5e 4 something like that

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2•5(16/2-2•3)-2<br> Simplified

Artyom0805 [142]

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2 years ago

Q.16 please<br> With steps

blsea [12.9K]

The equations

$2x^2+9x-5=0$

and

$2\left(t-\dfrac12\right)^2+9\left(t-\dfrac12\right)-5=0$

are really the same, we're just setting $x=t-\dfrac12$ , or $t=x+\dfrac12$ .

$2x^2+9x-5=(2x-1)(x+5)=0\implies x=\dfrac12,x=-5$

So we get

$t=\dfrac12+\dfrac12=1,t=-5+\dfrac12=-\dfrac92$

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2 years ago