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Inessa05 [86]
2 years ago
14

Classify the following based on sides and angles.​

Mathematics
1 answer:
matrenka [14]2 years ago
3 0

Answer:

D. right; scalene

Step-by-step explanation:

As you can see in the diagram you have a 90, 50, and 40 degrees angles. Because one of the angles is equal to 90 degrees (a right angle) this triangle can be classified as a right triangle.

No congruent sides are shown.... That means it's a scalene.

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Amy was given an amount of money, m, for good grades on her report card. She spent $15.00 and now has $25.32. How much money did
Vaselesa [24]

Answer:

c

Step-by-step explanation:

8 0
2 years ago
PRECALCULUS please help​
sergejj [24]

Answer:

<h2>( f - g)(x)  =  \frac{2x -  \sqrt{x} + 14 }{3x}</h2>

Step-by-step explanation:

f(x) =  \frac{2x + 6}{3x}  \\  \\ g(x) =  \frac{ \sqrt{x}  - 8}{3x}

To find ( f - g)(x) , subtract g(x) from f(x)

That's

( f - g)(x) =  \frac{2x + 6}{3x}  -  \frac{ \sqrt{x}  - 8}{3x}

Since they have a common denominator that's 3x we can subtract them directly

That's

\frac{2x  +  6}{3x}  -  \frac{ \sqrt{x}  - 8}{3x}    =  \frac{2x  + 6 - ( \sqrt{x} - 8) }{3x}  \\  =  \frac{2x + 6 -  \sqrt{x} + 8 }{3x}  \\  =  \frac{2x -  \sqrt{x} + 6 + 8 }{3x}

We have the final answer as

<h3>( f - g)(x)  =  \frac{2x -  \sqrt{x} + 14 }{3x}</h3>

Hope this helps you

6 0
3 years ago
I need help with the bottom one the absolute value one
astra-53 [7]

Absolute value is simply the non-negative version of the number regardless of its symbol

So for the absolute value of 20? the answer is just 20.

For reference, the absolute value of -20 is also just 20.

Hope the explanation helps :)

5 0
2 years ago
Read 2 more answers
Which expression is equivalent to the given expression
MA_775_DIABLO [31]

Answer:

i think the answer is A. 2x^3y^2

7 0
1 year ago
You might need:
mash [69]

Answer:

lesser x: - 6

greater x: 2

Step-by-step explanation:

f(x) = (x + 2)² – 16

(x + 2)² – 16 = 0

(x + 2 + 4) (x + 2 - 4) = 0

(x + 6)(x - 2) = 0

roots (zero): x = -6 or x = 2

8 0
3 years ago
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