The pass rusher, which is typically line up on the line of scrimmage.
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Answer:
73
Step-by-step explanation:
Original number: XY
x = 3y - 2
10y + x = (10x + y) / 2 + 1/2
substitution: 10y + 3y - 2 = 13y - 2 = (10 * (3y - 2) + y) / 2 + 1/2
* 2 both sides and simplify: 26y - 4 = 31y - 19
31y - 26y = -4 + 19
5y = 15
y = 3
x = 7
Original number: 73
The width would be 1 inch.
Given: L = length = 5W; P = perimeter = 2(L+W) = 12 inches
Required: W = width;
Formula: P=2(L+W)
Solution:
12 in = 2 (L + W)
6 in = L + W
6 in = 5W + W
6 in = 6W
1 in = W
Cross check:
P = 2(L + W)
12 in = 2(5 in + 1 in)
12 in = 2(6 in)
12 in = 12 in
