Factor completely 2c^3-22c^2+48c
1 answer:
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Computing the limit directly:
Alternatively, you can recognize the limit as being equivalent the derivative of <em>f(x)</em> at <em>x</em> = 2, in which case differentiating and plugging in 2 gives
<em>f'(x)</em> = 2<em>x</em> + 1 => <em>f'</em> (2) = 5
The sequence is
740, 707.60,675.20,642.80,...
Here first term is 740, and common difference, d is
Now we use the formula of nth term, which is
Substituting the values of a,n and d, we will get
Correct option is the second option .