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2 years ago

Factor completely 2c^3-22c^2+48c

Mathematics

1 answer:

Bingel [31]2 years ago

7 0

Answer:

2c(c - 3)(c - 8)

Step-by-step explanation:

Hello!

Factor:

2c³ - 22c² + 48c
2c(c² - 11c + 24)

Think: What two numbers multiply to 24, and add up to -11?

Answer: -8 and -3

Split up the -11c into -8c and -3c:

2c(c² - 8c - 3c + 24) (factor each pair)
2c( c(c - 8) - 3(c - 8))
2c(c - 3)(c - 8)

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Otherwise, you can derive the same result. Let $\theta=\sin^{-1}\dfrac12$ , so that $\sin\theta=\dfrac12$ . $\sin^{-1}$ is bounded, so we know $-\dfrac\pi2\le\theta\le\dfrac\pi2$ . For these values of $\theta$ , we always have $\cos\theta\ge0$ .

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