You can solve all of these by using the distance formula. I have shared it below.
Point/Slope Form of an equation!
(5,3)
slope of -2/5
x= 5
y = 3
y - y1 = m(x-x1)
y - 3 = -2/5(x-5)
y - 3 = -2/5x + 2
y = -2/5x + 5
x intercept of 5
Answer:
RL=5x+28 and
RO=8X-11
diagonal of square bisect equally the side
:.5x+28=8x-11
11+28=8x-5x
39=3x
x=39/3=13
<u>RY</u><u>=</u><u>RL</u><u>=</u><u>5</u><u>x</u><u>+</u><u>2</u><u>8</u><u>=</u><u>5</u><u>×</u><u>1</u><u>3</u><u>+</u><u>2</u><u>8</u><u>=</u><u>9</u><u>3</u><u>If the answer is 93, move to </u><u>answer</u><u>.</u>
Answer: ( -0.731, 0.682)
Step-by-step explanation:
The unit vector is defined as a vector that points in the same direction as our vector (137 degrees from the x-axis) and has a magnitude of 1.
Knowing the angle, is really simple to do it.
First, we know that for a radius R and an angle A, the rectangular coordinates can be written as:
x = R*cos(A)
y = R*sin(A)
And if we want that the magnitude/modulus of our vector to be 1, then R = 1, and we know that A = 137°
x = 1*cos(137°) = -0.731
y = 1*sin(137°) = 0.682
Then the unit vector is: ( -0.731, 0.682)