The answer is 3/4 l did on iready and l got it right
Answer:
80 markers
Step-by-step explanation:
Set it up as an equation.
markers/erasers 5/2=x/32
Cross multiply to get 160=2x
x=80
Answer:
The ball will go to maximum height of 56.25 meters.
Step-by-step explanation:
It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec
Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :

h = 0
..............(1)
We need to find the maximum height reached by the ball. For maximum height,


t = 1.875 seconds
Put the values of t in equation (1). So,

h(t) = 56.25 meters
So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.
Yap,
It seems to me that there are two answers. Both y = .5x and y = 12x. Direct variation is what I'm thinking of so hopefully this helps.
BTW - with Direct Variation, the line will go through (0, 0).
Answer:
Step-by-step explanation:
15/2 = 7.5 and (7.5)^2 = 56.25 so
x^2 + 15x + 56.25 = 49 + 56.25
x^2 + 15x + 56.25 = 105.25.