3. Determine the lateral and total surface<br> area of the pyramid.

Brainliest will be given to whoever has the correct answer

Shkiper50 [21]

Answer:

2

Step-by-step explanation:

7 0

2 years ago

What is the volume of the cylinder with a radius of 8 and height of 4<br><br>

mr Goodwill [35]

Answer:

Hey there!

The formula for cylinder volume is $r^2h\pi$ , where r is the radius, h is the height, and $\pi$ is a constant, roughly equal to 3.14.

Substituting all of these values into the equation:

$8^2(4)(3.14)$

$804.84\\$

Thus, the volume for the cylinder is 804.84 units cubed.

Hope this helps :)

6 0

3 years ago

Read 2 more answers

At every company meeting, the president speaks for 20 minutes and then takes questions from her employees. Let q represent the n

ololo11 [35]

Answer:

t = 20 + q (minutes)

Step-by-step explanation:

The meeting consists of speaking and Question & Answer (Q&A) sessions.

Speaking session = 20 minutes

Q&A session = q minutes

Total number of minutes spent for the two sessions = 20 + q (minutes)

But total number of minutes meeting lasted = t minutes.

Therefore, t = 20 + q (because they both represent the total number of minutes the meeting lasted)

4 0

3 years ago

which of the following gives an equation of a line that passes through the point (6 over 5, -19 over 5) and is parallel to the l

victus00 [196]

One equation for this would be

$y = \frac{41}{16} x-\frac{55}{8}$

We start by finding the slope between the two points:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-12-\frac{-19}{5}}{-2-\frac{6}{5}}
\\
\\=(-12+\frac{19}{5}) \div (-2-\frac{6}{5})
\\
\\=(\frac{-60}{5}+\frac{19}{5}) \div (\frac{-10}{5}-\frac{6}{5})
\\
\\=\frac{-41}{5} \div \frac{-16}{5}=\frac{-41}{5} \times \frac{-5}{16}=\frac{41}{16}$

A line parallel to this one will have the same slope. We will use point-slope form to write our equation:

$y-y_1=m(x-x_1)
\\
\\y-\frac{-19}{5}=\frac{41}{16}(x-\frac{6}{5})
\\
\\y+\frac{19}{5}=\frac{41}{16}x- \frac{41}{16} \times \frac{6}{5}
\\
\\y+\frac{19}{5}=\frac{41}{16}x-\frac{246}{80}
\\
\\y+\frac{304}{80}=\frac{41}{16}x-\frac{246}{80}
\\
\\y=\frac{41}{16}x-\frac{246}{80}-\frac{304}{80}
\\
\\y=\frac{41}{16}x-\frac{550}{80}
\\
\\y=\frac{41}{16}x-\frac{55}{8}$

6 0

3 years ago

The Japanese 5 yen coin has a hole in the middle. What are the possible ways to calculate the difference between the distances f

ipn [44]

Answer:a) Subtract the two diameters and multiply by 3.14

d) Subtract the circumference of the hole from the circumference of the coin

Step-by-step explanation:

i just did the assignment

9 0

2 years ago

Read 2 more answers

3. Determine the lateral and total surface area of the pyramid.