Answer:
85 parking spaces
Step-by-step explanation:
Given that :
Parking spaces on floors :
Let first floor = x
Second floor = 2x
Third floor = 2x + 3
Total parking spaces = 428
THEREFORE ;
x + 2x + 2x + 3 = 428
5x + 3 = 428
5x = 428 - 3
5x = 425
x = 425 / 5
x = 85
Hence, there are 85 parking spaces on the first floor
It is adding one little percentage of increase here. or, 1.1 each time....hope that this helps.
200 dollars like the answer please
Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
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Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).
Answer:
Question is not clear please post question clearly lots of question marks.