Answer:
At 12:18, eighteen minutes after noon, the number of bytes infected be the same in both computers.
Step-by-step explanation:
1. Lets name PC1 the first computer and PC2 the second computer, so, at noon 1 byte of PC1 is infected with the virus, that is:
PC1
Hour Bytes infected
12:00 1
Then, every minute thereafter, the number of bytes is multiplied by two, that is:
PC1
Hour Bytes infected
12:01 2
12:02 4
12:03 8
12:04 16
12:05 32
12:06 64
12:07 128
12:08 256
12:09 512
12:10 1024
12:11 2048
12:12 4096
2. In the minute 12 after noon, 1 byte of PC2 is infected, meanwhile PC1 has 4096 bytes infected as shown above, that is:
PC1 PC2
Hour Bytes infected Bytes infected
12:12 4096 1
And each minute thereafter, the number of bytes infected in PC2 multiplied by eight, that is:
PC1 PC2
Hour Bytes infected Bytes infected
12:13 8192 8
12:14 16384 64
12:15 32768 512
12:16 65536 4096
12:17 131072 32768
12:18 262144 262144
Therefore, at 12:18, eighteen minutes after noon the number of bytes infected be the same in both computers.
Answer:
Agree
Step-by-step explanation:
They are the same group, just that they are referred to more as natural numbers.
719-225=494
hopes this helps :) :D :)
Answer:
Ella grew 
of an inch more
Step-by-step explanation:
For this problem, you want to subtract Ben's growth from Ella's.
This expression would be 
-
.
To work these out, they must have the same denominator (which should be the lowest common multiple or LCM).
In this case, the LCM is 12, so you want to multiply each side so the denominator is 12. This means the first fraction should be multiplied by 
and the second by 
.
This makes the expression 
-
, which equals .
**This content involves adding and subtracting fractions, which you may want to revise. I'm always happy to help!
