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Anettt [7]
3 years ago
8

Consider z = 3StartRoot 3 EndRoot + 3i. What happens to the modulus and argument when z is raised to the 4th power?

Mathematics
2 answers:
vfiekz [6]3 years ago
8 0

Answer:

Its A on edge

The modulus increases by a factor of 216, and the argument increases by StartFraction pi Over 2 EndFraction.

Step-by-step explanation:

Crazy boy [7]3 years ago
6 0

Answer:

A

Step-by-step explanation:

Edge2021

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After painting the fence steve and janet realize that their house also needs painting. But steve will have to do the painting hi
gladu [14]

Answer:

Therefore, Steve will paint house for 20.6 days.

Step-by-step explanation:

We know that Steve determines that it would take them 9 days to paint the house together (if they were both healthy) and that it would take Janet (when healthy) 16 days to paint the house alone.

We conclude that in 1 day Janet painted 1/16 of the house. In nine days, Janet painted 9/16 of house.

So, 7/16 of house paint Steve in nine days.

We have the following proportion:

\frac{7}{16}:9=1:x\\\\\frac{7}{16}x=9\\\\x=9\cdot \frac{16}{7}\\\\x=20.6

Therefore, Steve will paint house for 20.6 days.

4 0
3 years ago
The letters for the word SCHOOL are placed in a hat. What is the probability of drawing the letter o out of the hat?
Cerrena [4.2K]

Answer: 2/6 or 1/3

Step-by-step explanation:

SCHOOL has 6 letters in it and two O's. Therefore, it would be 2/6 or simplified it would be 1/3.

That was FUN!

8 0
2 years ago
ms olivieri’s class plays a game in teams each team has the same number of students the ratio of teams to players is 8:32 how ma
Bezzdna [24]

Answer:

32 students

Step-by-step explanation:

8 teams

32 students

7 0
3 years ago
Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0
3 years ago
Whats 20 times 30 ÷ 65
vlabodo [156]
20 * (30 ÷ 65) = <span>9.23076923077</span>
4 0
3 years ago
Read 2 more answers
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