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2 years ago

Does the dilated image represent an enlargement, reduction, or neither?

Mathematics

2 answers:

IRINA_888 [86]2 years ago

5 0

Answer: B reduction

Step-by-step explanation:

The blue triangle is the pre-image. (The original image before it was changed) The green triangle is the mapped image (the image after it was changed) we know this because of the ‘ marks after each point. So the original blue triangle was reduced in size to form the green triangle.

madreJ [45]2 years ago

5 0

Answer:reduction

Step-by-step explanation:

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Help pls! 37 points.

Mademuasel [1]

Answer:

7 squares

Step-by-step explanation:

Key skills: Counting, Averages

1) Based on what I counted, there are 11 columns, and 53 squares. If you want an average of 5 squares per column and you have 12 columns, the total number of squares you want is 60.

2) Since there are already 53 squares present, you need 60-53 = 7 squares more.

Hope you understood and have a nice day!!

5 0

3 years ago

Read 2 more answers

What is the measure of angle C?

tekilochka [14]

Answer:

19x because I add them together then add the x at the end.

6 0

3 years ago

Please solve and explain the steps

Crazy boy [7]

Answer/Step-by-step explanation:

First isolate the variable.

-x+6≥10

-6 -6

-x≥4

Divide by negative 1

x≥-4

So the answers would be -3.9, 4, -4, 3.9, 0, 7, 4.01

5 0

2 years ago

The desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5. To test whether the true average

lukranit [14]

Answer:

We conclude that the true average percentage of Silicon Dioxide is smaller than 5.5.

Step-by-step explanation:

We are given that the desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5.

16 independently obtained samples are analyzed and a sample mean of 5.25 was obtained. Suppose that the percentage of SiO2 in a sample is normally distributed with a sigma of 0.3.

Let $\mu$ = true average percentage of Silicon Dioxide.

So, Null Hypothesis, $H_0$ : $\mu$ $\geq$ 5.5 {means that the true average is greater than or equal to 5.5}

Alternate Hypothesis, $H_A$ : $\mu$ < 5.5 {means that the true average is smaller than 5.5}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean percentage of Silicon Dioxide = 5.25

σ = population standard deviation = 0.3

n = sample size = 16

So, the test statistics = $\frac{5.25-5.5}{\frac{0.3}{\sqrt{16} } }$

= -3.33

The value of z test statistics is -3.33.

Now, the P-value of the test statistics is given by;

P-value = P(Z < -3.33) = 1 - P(Z $\leq$ 3.33)

= 1 - 0.9996 = 0.0004

Since, the P-value of the test statistics is less than the level of significance as 0.0004 < 0.01, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true average percentage of Silicon Dioxide is smaller than 5.5.

7 0

3 years ago

Read 2 more answers

Mario walks 7 blocks east from his home and arrives at his favorite restaurant. When he arrives, he discovers that he dropped h

Alex

7+ -5= 2

The answer is 2 blocks east

4 0

3 years ago