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3 years ago

16q3-48q2+32q what would be the steps on how to do this? please?

Mathematics

1 answer:

Sholpan [36]3 years ago

8 0

Answer:

Its nothing complicated, you just have to combine all the like terms, just make sure the lvariables are the same before combining of course.

so assuming the gaps missng are exponents

the solution is the same exact thing

it can’t be simplified anymore since 16q^3 or -48q^2 can’t due to different exponents which thefore can’t combine

same with 32 q, nothing combines

The answer is the original expression

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I NEED HELP PLEASE HELP ME

alex41 [277]

Answer:

Length should be 15 cm and width should be 5 cm

Step-by-step explanation:

5 * 3 = 15

15+15+5+5=40

6 0

3 years ago

Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked h

Andrews [41]

Answer:

[0.9 months, 32.69 months]

Step-by-step explanation:

The mean is

$\bf \bar x=\frac{5+17+12+21+29}{5}=16.8$

The standard deviation is

$\bf s=\sqrt{\frac{(5-16.8)^2+(17-16.8)^2+(12-16.8)^2+(21-16.8)^2+(29-16.8)^2}{5}}=8.1092$

Now, we have to find two values a and b such that the area under the Normal curve with mean 16.8 and standard deviation 8.1092 between a and b equals <em>95% = 0.95 </em>

Using a spreadsheet we find these values are

a = 0.906

b = 32.694

<h3>(See picture) </h3>

and our 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program rounded to two decimal places is

[0.9 months, 32.69 months]

4 0

3 years ago

1. f(x) = 2x + 6 Evaluate f(2)

fredd [130]

1) f(x)=2x+6
f(2)=2(2)+6
=4+6
=10

2)f(x)=3x
f(a+1)=3(a+1)
=3a+3
3)f(x)=3x-1 and g(x)=5x+3

f(2)=3(2)-1
f(2)=6-1
=5
g(3)=5x+3
=5(3)+32
=15+3
=18

f(2)+f(3)=5+18
=23.

7 0

3 years ago

Read 2 more answers

Write an equation in slope-intercept form of the line with the parametric equations x=2t and y=1-t

pentagon [3]

Answer: -x/2 + 1

Step-by-step explanation:

write t in terms of x

x = 2t

t = x/2

substitute t in y

y = 1 - t