Answer:
1.) It's 20th century painting
2.) 0.5 probability
Step-by-step explanation:
If the universal = 60
We need to first get the value of X. That is,
x (x - 2) + x + 2x + 8 + 10 = 60
First open the bracket
x^2 - 2x + x + 2x + 8 + 10 = 60
x^2 + x + 18 = 60
x^2 + x - 42 = 0
Factorise the above equation
x^2 + 7x - 6x - 42 = 0
x (x + 7) -6(x + 7) = 0
x = 6 or - 7
Since x can't be negative, so we will ignore -7
The value for T = 6(6 - 2) = 6×4 = 24
The value for B = 2(6) + 8 = 12 + 8 = 20
If a painting is chosen from random,
If it's from 20th century, the probability will be 34/60 = 0.567
If it's from British painting, the probability will be 30/60 = 0.5
We can therefore conclude that it's from 20th century painting since it has higher value of probability.
The the probability of choosing a British painting will be 30/60 = 0.5
Answer:
A 80 points, B 89%
Step-by-step explanation:
Look At The Attachment::
Answer:

Step-by-step explanation:
The logistic equation is the following one:

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.
In this problem, we have that:
Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that
.
The number of fish tripled in the first year. This means that
.
Using the equation for P(1), that is, P(t) when
, we find the value of r.









Applying ln to both sides.


This means that the expression for the size of the population after t years is:

Answer:
6. <u> (2x - 1) </u>
(3x + 2)
8. <u> y - 3 </u>
y² - 3y + 9
Step-by-step explanation:
6. <u> 2x² + 9x - 5</u>
3x² + 17x + 10
= <u>(2x - 1) (x + 5)</u>
3x² + 17x + 10
= <u>(2x - 1) (x + 5)</u>
(3x + 2) (x + 5)
= <u> (2x - 1) </u>
(3x + 2)
8. <u>y² - 9 </u>
y³ + 27
= <u> (y + 3) (y - 3)</u>
y³ + 27
= <u> (y + 3) (y - 3) </u>
(y+3) (y² - 3y + 9)
= <u> y - 3 </u>
y² - 3y + 9