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Andrei [34K]
2 years ago
7

Before starting to play the roulette in a casino you want to look for biases that you can exploit. Youtherefore watch 100 rounds

that result in a number between 1 and 36 and you count the number ofrounds for which the result is odd. If the count exceeds 55, you decide that the roulette is not fair.Assuming that the roulette is fair, find an approximation for the probability that you will makethe wrong decision.
Mathematics
1 answer:
never [62]2 years ago
8 0

Answer:

P(n>55)=0.1357

Step-by-step explanation:

From the question we are told that:

Sample size n=100

Sample space n'=36

Generally the equation for the mean number of times odds appears is mathematically given by

\=x_o=hp

\=x_o=100*0.5

\=x_o=50

Generally the equation for standard deviation is mathematically given by

\sigma=(hp(1-p))^{1/2}\\\sigma=(50(0.5))^{1/2}

\sigma=5

Therefore probability to make wrong decision P(n>55)

P(n>55)=1-P(z55)=1-P(z55)=1-0.86

P(n>55)=0.1357

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Answer:

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Step-by-step explanation:

If the universal = 60

We need to first get the value of X. That is,

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First open the bracket

x^2 - 2x + x + 2x + 8 + 10 = 60

x^2 + x + 18 = 60

x^2 + x - 42 = 0

Factorise the above equation

x^2 + 7x - 6x - 42 = 0

x (x + 7) -6(x + 7) = 0

x = 6 or - 7

Since x can't be negative, so we will ignore -7

The value for T = 6(6 - 2) = 6×4 = 24

The value for B = 2(6) + 8 = 12 + 8 = 20

If a painting is chosen from random,

If it's from 20th century, the probability will be 34/60 = 0.567

If it's from British painting, the probability will be 30/60 = 0.5

We can therefore conclude that it's from 20th century painting since it has higher value of probability.

The the probability of choosing a British painting will be 30/60 = 0.5

5 0
3 years ago
5.Sophia got 68 points correct on her math test, which earned her an 85%. Her friend Tami
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4 0
2 years ago
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Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
kotegsom [21]

Answer:

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Step-by-step explanation:

The logistic equation is the following one:

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In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

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P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

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e^{r} = \frac{537600}{137600}

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\ln{e^{r}} = \ln{3.91}

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Answer:

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