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3 years ago

What is an equation of the line that passes through the point (-3,-1) and is

Mathematics

1 answer:

Yuri [45]3 years ago

6 0

Answer:

y = -2x - 7

Step-by-step explanation:

x - 2y = 6

-2y = -x + 6

Divide the whole equation by (-2)

$\frac{-2y}{-2}=\frac{-x}{-2}+\frac{6}{-2}\\\\y = \frac{1}{2}x - 3$

slope = 1/2

Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/2)

$=(-1)*\frac{2}{1}\\\\= -2$

(-3, - 1)

y -y1 = m(x -x1)

y - [-1] = -2(x - [-3])

y + 1 = -2(x + 3)

y + 1= x* (-2) + 3*(-2)

y + 1 = -2x - 6

y = -2x - 6 - 1

y = -2x - 7

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3 years ago

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2 years ago

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2 years ago

Write the slope-intercept form of the equation of the line; (-5,-4) and prep. To y equals 5x plus 1

ohaa [14]

Answer:

$y=-\frac{1}{5} x-5$

Step-by-step explanation:

The given line is defined by: $y=5x+1$ , where we see that the slope is 5 and the y-intercept 1.

In order to find a line perpendicular to the given one, we need it to have a slope that is the "opposite of the reciprocal" of the given slope.

"Opposite" means it would have its sign inverted (in our case from positive to negative); and "reciprocal means that instead of 5, it would be its reciprocal: $\frac{1}{5}$ .

We can write this new line with such slope, and try to find its y-intercept (b) by using the given condition that requires it to go through the point (-5,-4) on he plane:

$y=-\frac{1}{5} x+b$

we require then that when $x=-5$ , the value of $y=-4$ .

Therefore: $-4=-\frac{1}{5} (-5)+b\\-4=\frac{5}{5} +b\\-4=1+b\\b=-4-1=-5$

Then our final answer is that the new line should have the form: $y=-\frac{1}{5} x-5$

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3 years ago