3 consecutive odd integers that the sum of the smallest and 4 times the largest is 61
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Hello! To find any number in the arithmetic sequence we can use a formula!
It is given by
The geometric sequence formula goes by
So for this we notice that there's a start of 5 and is being added 3 to get 8.
and then each time it is added by 2 more to get the next time
5
5+ 3 = 8
8 + 5 = 13
13 + 7 = 20
20 + 9 = 29
29 + 11 = 41
41 + 13 = 54
54 + 15 = 69
69 + 17 = 83
Your formula is
Where n starts at 2 not 1
It is given by
The geometric sequence formula goes by
So for this we notice that there's a start of 5 and is being added 3 to get 8.
and then each time it is added by 2 more to get the next time
5
5+ 3 = 8
8 + 5 = 13
13 + 7 = 20
20 + 9 = 29
29 + 11 = 41
41 + 13 = 54
54 + 15 = 69
69 + 17 = 83
Your formula is
Where n starts at 2 not 1