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Anastasy [175]
3 years ago
6

3 consecutive odd integers that the sum of the smallest and 4 times the largest is 61

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

  9, 11, 13

Step-by-step explanation:

Let n represent the smallest of the integers. Then n+4 is the largest of them. The given total is ...

  n + 4(n+4) = 61

  5n +16 = 61

  5n = 45 . . . . . . subtract 16

  n = 9 . . . . . . . . divide by 5

The smallest of the integers is 9, so the other two are 11 and 13.

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Moby practiced solving addition and subtracting problems, but he made a mistakes! Explain any error you find, and include what’s
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Answer:

3/4 - 5/12 = 4/12 - 5/12 = -1/12

Step-by-step explanation:

Moby's  addition and subtracting problem is as follows: Let us break the problem into solvable parts.

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we will find the common factor of the denominator which are 4 and 12. The common factor is 12. We divide 12 by both denominator and multiply by the numerator .

3/4-5/12 = (9 - 5)/12 = 4/12 . This is his first error . 3/4 - 5/12 is equal to 4/12 not 3/12.

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The correct answer combination should be as follows.

3/4 - 5/12 = 4/12 - 5/12 = -1/12

4 0
3 years ago
8g-14g+22=37 what does g equal
Sphinxa [80]
If you would like to solve the equation 8 * g - 14 * g + 22 = 37 for g, you can calculate this using the following steps:

8 * g - 14 * g + 22 = 37
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Result: g equals to - 5/2.
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