Question

3 consecutive odd integers that the sum of the smallest and 4 times the largest is 61

Answer 1

Answer:

  9, 11, 13

Step-by-step explanation:

Let n represent the smallest of the integers. Then n+4 is the largest of them. The given total is ...

  n + 4(n+4) = 61

  5n +16 = 61

  5n = 45 . . . . . . subtract 16

  n = 9 . . . . . . . . divide by 5

The smallest of the integers is 9, so the other two are 11 and 13.