3 years ago

3 consecutive odd integers that the sum of the smallest and 4 times the largest is 61

Mathematics

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer:

9, 11, 13

Step-by-step explanation:

Let n represent the smallest of the integers. Then n+4 is the largest of them. The given total is ...

n + 4(n+4) = 61

5n +16 = 61

5n = 45 . . . . . . subtract 16

n = 9 . . . . . . . . divide by 5

The smallest of the integers is 9, so the other two are 11 and 13.

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