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astraxan [27]
3 years ago
13

Can you anyone please help me​

Computers and Technology
1 answer:
Yuliya22 [10]3 years ago
3 0

Answer:

Option C I think

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What could have made you redesign your plan? Select 3 options.
Masteriza [31]

Answer:

so that their username will still be used and so the can renember the username

Explanation:

that is why

5 0
3 years ago
How to delete nonsense answers to questions I added? please help
DiKsa [7]

in order to delete answers from your questions, you have to rate them one star , or at least that's what I do, and then report it and then brainly will determine if it's something that needs to be taken down or not

5 0
3 years ago
Matching parentheses. An math expression may have a number of parentheses like (, ), [, ], { and }. Each openning parenthesis (,
Solnce55 [7]
C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}


Sample Input/Output is attached

3 0
2 years ago
Lean production systems are sometimes referred to as pull systems because demand from customers activates the production actions
fredd [130]

Answer:

a.Kanban Pull System

Explanation:

Part of a lean manufacturing technique, is the pull system and it is a production or service oriented process used to reduce waste. A pull system is a Lean technique for reducing the waste of any production process. Using a pull system allows you to begin new work only when there is either customer demand for it or goods are required by the next step within the production process. Applying a pull system allows you to start new work only when there is a customer demand for it. This gives you the opportunity to reduce overhead and optimize storage costs.

Kanban is based on a set of principles and practices that are easy to understand. Implementing them is also fairly simple since you do not need to make any serious changes to your existing process. But it is key that you understand the methodology and stick with the core practices if you want to successfully implement a Kanban pull system.

7 0
3 years ago
Read 2 more answers
To guarantee that the member variables of a class are initialized, you use ____.
Leya [2.2K]
A constructor, member initialization lists and also the default member initializer. Here you see all three (in reality you choose one construct per variable).

class A
{
  public:
    int x = 0;

   A() : x(1)
   {
      x = 2;
   }
};
8 0
3 years ago
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