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wlad13 [49]

Answer:

10

Explanation:

Pointer arithmetic is tricky. The address is incremented by the sizeof the pointed element. A short is 2 bytes.

So adding 10 adds 20 bytes to the starting address of arr[].

In the expression, you're adding 10-6 = 4 to the start of the array, so you're pointing at the fifth element, arr[4] which is 10.

8 0

2 years ago

The mathematical constant Pi is an irrational number with value approximately 3.1415928... The precise value of this constant ca

tatiyna

Answer:

I am writing a Python program:

def approxPIsquared(error):

previous = 8

new_sum =0

num = 3

while (True):

new_sum = (previous + (8 / (num ** 2)))

if (new_sum - previous <= error):

return new_sum

previous = new_sum

num+=2

print(approxPIsquared(0.0001))

Explanation:

I will explain the above function line by line.

def approxPIsquared(error):

This is the function definition of approxPlsSquared() method that takes error as its parameter and approximates constant Pi to within error.

previous = 8 new_sum =0 num = 3

These are variables. According to this formula:

Pi^2 = 8+8/3^2+8/5^2+8/7^2+8/9^2+...

Value of previous is set to 8 as the first value in the above formula is 8. previous holds the value of the previous sum when the sum is taken term by term. Value of new_sum is initialized to 0 because this variable holds the new value of the sum term by term. num is set to 3 to set the number in the denominator. If you see the 2nd term in above formula 8/3^2, here num = 3. At every iteration this value is incremented by 2 to add 2 to the denominator number just as the above formula has 5, 7 and 9 in denominator.

while (True): This while loop keeps repeating itself and calculates the sum of the series term by term, until the difference between the value of new_sum and the previous is less than error. (error value is specified as input).

new_sum = (previous + (8 / (num ** 2))) This statement represents the above given formula. The result of the sum is stored in new_sum at every iteration. Here ** represents num to the power 2 or you can say square of value of num.

if (new_sum - previous <= error): This if condition checks if the difference between the new and previous sum is less than error. If this condition evaluates to true then the value of new_sum is returned. Otherwise continue computing the, sum term by term.

return new_sum returns the value of new_sum when above IF condition evaluates to true

previous = new_sum This statement sets the computed value of new_sum to the previous.

For example if the value of error is 0.0001 and previous= 8 and new_sum contains the sum of a new term i.e. the sum of 8+8/3^2 = 8.88888... Then IF condition checks if the

new_sum-previous <= error

8.888888 - 8 = 0.8888888

This statement does not evaluate to true because 0.8888888... is not less than or equal to 0.0001

So return new_sum statement will not execute.

previous = new_sum statement executes and now value of precious becomes 8.888888...

Next num+=2 statement executes which adds 2 to the value of num. The value of num was 3 and now it becomes 3+2 = 5.

After this while loop execute again computing the sum of next term using new_sum = (previous + (8 / (num ** 2)))

new_sum = 8.888888.. + (8/(5**2)))

This process goes on until the difference between the new_sum and the previous is less than error.

screenshot of the program and its output is attached.

6 0

3 years ago

Create a program that includes a function called toUpperCamelCase that takes a string (consisting of lowercase words and spaces)

astraxan [27]

Answer:

#include<iostream>

using namespace std;

//method to remove the spaces and convert the first character of each word to uppercase

string

toUpperCameICase (string str)

{

string result;

int i, j;

//loop will continue till end

for (i = 0, j = 0; str[i] != '\0'; i++)

{

if (i == 0) //condition to convert the first character into uppercase

{

if (str[i] >= 'a' && str[i] <= 'z') //condition for lowercase

str[i] = str[i] - 32; //convert to uppercase

}

if (str[i] == ' ') //condition for space

if (str[i + 1] >= 'a' && str[i + 1] <= 'z') //condition to check whether the character after space is lowercase or not

str[i + 1] = str[i + 1] - 32; //convert into uppercase

if (str[i] != ' ') //condition for non sppace character

{

result = result + str[i]; //append the non space character into string

}

//return the string

return (result);

}

//driver program

int main ()

{

string str;

char ch;

//infinite loop

while (1)

{

fflush (stdin);

//cout<< endl;

getline (cin, str); //read the string

//print the result

//cout<< endl << "Q";

// cin >> ch; //ask user to continue or not

ch = str[0];

if (ch == 'q' || ch == 'Q') //is user will enter Q then terminatethe loop

break;

cout << toUpperCameICase (str);

cout << endl;

}

return 0;

}

8 0

2 years ago

A block style business letter is

Molodets [167]

Answer:

Block style is a special style or format that is adopted to write Business Letters.

Explanation:

We all know that for writing Business Letters a formal style is adopted in order to convey important information regarding business matters.

So by following Block Style in the Business Letters we mean to write the letter according to the rules below:

Text for the letter should be justified Left completely.

Single spacing should be used for text.

Double spacing should be used for paragraphs.

1 inch margin should be left on each side.

Built-in Letter Wizard for formatting can also be used while dealing with BLOCK STYLE FOR BUSINESS LETTERS.

I hope it will help you!

7 0

3 years ago

The acronym LAH stands for

Nina [5.8K]

D.Limited Access Highway

5 0

3 years ago

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